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Marta_Voda [28]
3 years ago
10

How are static variables and methods created in Java? What happens if a non-static method of a class tries to access a static va

riable of that class? What happens to the static variables of a class once the class has no instances?
Computers and Technology
1 answer:
9966 [12]3 years ago
4 0

Answer:

Static variables are the variables decaraed with keyword static, static variables must be deacraled inside the class body, means we can not declare a static variable inside a method or consttructor, static variable belongs to class, for a class only one copy is created for static variable and used by all the objects/instances.

Static variable can access with class name like

X.i

Static method are the methods defined with static keyword, static method are also part of a class, we can access static meethod using class name like

X.printI()  

Explanation:

class X

{

//to create a static variable we need use static keyword with variable name like

public static int i;

// to create a static method we need to use static keyword while defining a method like

public static void printHello() {

 System.out.println("Hello");

}

/*

 * A non static method can access static variable of a class there is no issue

 * with that we can use a static variable in a non static method like

 */

public void printI() {

 System.out.println(i);

}

/*

 * As long as the class exist in JVM static variables will be there, as static

 * variable belong to class not with the instance,

 * it does not matters if there are instance exist or not

 */

}

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Delvig [45]

Answer:

Program.java  

import java.util.Scanner;  

public class Program {  

   public static boolean isPalindrome(String str){

       int start = 0, end = str.length()-1;

       while (start < end){

           if(str.charAt(start) != str.charAt(end)){

               return false;

           }

           start++;

           end--;

       }

       return true;

   }  

   public static int countPalindromePairs(String[] inarr){

       int count = 0;

       for(int i=0; i<inarr.length; i++){

           for(int j=i+1; j<inarr.length; j++){

               StringBuilder sb = new StringBuilder();

               sb.append(inarr[i]).append(inarr[j]);

               if(isPalindrome(sb.toString())){

                   count++;

               }

           }

       }

       return count == 0 ? -1 : count;

   }

   public static void main(String[] args) {

       Scanner sc = new Scanner(System.in);

       String line = sc.next();

       String[] inarr = line.split(",");

       int count = countPalindromePairs(inarr);

       System.out.println("RESULT: "+count);

   }

}

Explanation:

OUTPUT:

3 0
3 years ago
Design and write a class that implements an ordered list type using a linked list, and a program that exercises and tests the cl
-Dominant- [34]

Answer:

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You've just installed a new video card in a user's Windows workstation. When the system is powered on the screen is blank. You
valentinak56 [21]

After having verified that the video cable is installed correctly we should check to see that the computer's RAM is correctly fastened to the motherboard and functional.

The question states that the video card being installed is new, therefore we can comfortably assume that the card itself is not the issue. Other computer components that can cause a blank screen immediately upon powering on the workstation are:

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however, assuming the installation was performed correctly, it is not likely to be caused by a bad video driver and a faulty monitor input is very improbable given that there are very few ways this can break to begin with.

A bad or missing hard drive may cause this kind of issue because the workstation will not have a windows file to boot. In most cases, this will not cause a completely blank screen without first allowing access to the BIOS.

After having verified that the video cable is installed correctly, the very next thing you should check is if the RAM is installed correctly. This is because the issue explained is exactly what will happen if a workstation attempts to boot without RAM, and also because it is the easiest fix among the possible causes and any troubleshooting should always be performed in order from the easiest fix to the most difficult.

To learn more visit:

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8 0
3 years ago
Write a method called findNames that meets the following specs: It takes two arguments: a list of strings, allNames, and a strin
Anna11 [10]

Answer:

public class Solution {

   public static void main(String args[]) {

       String[] allNames = new String[]{"Bob Smith", "Elroy Jetson", "Christina Johnson", "Rachael Baker", "cHRis", "Chris Conly"};

       String searchString = "cHRis";

       

       findNames(allNames, searchString);

   }

   

   public static void findNames(String[] listOfName, String nameToFind){

       ArrayList<String> resultName = new ArrayList<String>();

       

       for(String name : listOfName){

           if (name.toLowerCase().contains(nameToFind.toLowerCase())){

               resultName.add(name);

           }

       }

       

       for(String result : resultName){

           System.out.println(result);

       }

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}

Explanation:

The class was created called Solution. The second line define the main function. Inside the main function; we initialized and assign an array called allNames to hold the list of all name. Then a String called searchString was also defined. The searchString is the string to search for in each element of allNames array. The two variables (allNames and searchString) are passed as argument to the findNames method when it is called.

The method findNames is defined and it accept two parameters, an array containing list of names and the name to search for.

Inside the findNames method, we initialized and assigned an ArrayList called resultName. The resultName variable is to hold list of element found that contain the searchString.

The first for-loop goes through the elements in the allNames array and compare it with the searchString. If any element is found containing the searchString; it is added to the resultName variable.

The second for-loop goes through the elements of the resultName array and output it. The output is empty if no element was found added to the resultName variable.

During comparison, the both string were converted to lower case before the comparison because same lowercase character does not equal same uppercase character. For instance 'A' is not same as 'a'.

8 0
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Mary has cleaned her data and is ready to determine the most efficient bus route. She starts by splitting the city into four reg
igomit [66]

ANSWER:

B.

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EXPLANATION:

Mary can check if there are other things or factors that might influence where the bus routes need to be prioritized. For example if the students' age is considered for the bus routes instead of regions. She can achieve this by

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