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inysia [295]
3 years ago
13

Examine the system of equations. Do you think the lines will intersect? Explain. y = 2x – 7 y = x – 7

Mathematics
2 answers:
Maru [420]3 years ago
8 0

Sample Response/Explanation: Yes, the lines will intersect because the slopes are different. Also, both lines have a y-intercept of -7, so they both include the point (0, –7).

Which did you include in your response? Check all that apply.

The lines will intersect.

The slopes are different.

The point (0, –7) lies on both lines.

guapka [62]3 years ago
7 0

Answer:

Indeed. The system of equations has a solution at point (0, -7).

Step-by-step explanation:

A system of linear equations is consistent only if exist a solution. Let equalize each expression to eliminate y and determine if a solution for x exist. That is:

2\cdot x - 7 = x - 7

2\cdot x - x = 7 - 7

x = 0

Therefore, the system of linear equations has a solution at point (0, -7).

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In short, Your Answer would be Option C

Hope this helps!
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2b^3 -5 b^2 +b+2. R 9/ b-4

Use synthetic division

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3 years ago
Which list shows the absolute values in order from least to greatest?
Maurinko [17]
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7 0
4 years ago
Read 2 more answers
♡LOTS OF POINTS TO RIGHT ANSWER♡
muminat

Answer:

\approx19.16

Step-by-step explanation:

To find the surface area of a cone, one uses the following formula,

A=(\pi)(r)(r+\sqrt{h^2+r^2}})

Where (r) is the radius of the base of the cone, and (h) is the height of the cone, (\pi) represents the numerical constant (3.1415...). In order for this formula to work, one needs the height of the cone. This can be found using the Pythagorean theorem. One can form a right triangle with the base's radius, the side length, and height of the cone, then solve for the height of the cone. The Pythagorean theorem states the following,

a^2+b^2=c^2

Substitute,

a^2+(1)^2=(5.1)^2

Simplify,

a^2+1=26.01

Inverse operations,

a^2=25.01\\a\approx5

Now one can use the formula to find the surface area of a cone, substitute in the given values, and solve,

A=(\pi)(r)(r+\sqrt{h^2+r^2}})

Substitute,

A=(\pi)(1)(1+\sqrt{5^2+1^2}})

A=(\pi)(1+\sqrt{25+1})\\A=\pi(1+\sqrt{26})\\A\approx 19.16

6 0
3 years ago
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