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soldier1979 [14.2K]

3 years ago

11

The midpoint of AB =

1 answer:

dolphi86 [110]3 years ago

4 0

Answer:

(-.5, 0)

Step-by-step explanation:

y ---- 2÷2=1, y-1= 1-1=0

x ---- 3÷2 =1.5, x-1.5= 1-1.5= -.5

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This table shows the number of miles that Sharon rode her bicycle in six weeks. If the mean number of miles she rode is 30, find

Nastasia [14]

(21 + 34 + x + 25 + 37 + 22) / 6 = 30
(139 + x) / 6 = 30 .....multiply both sides by 6
139 + x = 30 * 6
139 + x = 180
x = 180 - 139
x = 41......so during week 3, she rode her bike 41 miles

5 0

3 years ago

One human year is said to be about 7 dog years. Cliff's dog is 5.5 years old in

SCORPION-xisa [38]

The dog is 38.5 years old

7 0

3 years ago

Read 2 more answers

The point P(1,1/2) lies on the curve y=x/(1+x). (a) If Q is the point (x,x/(1+x)), find the slope of the secant line PQ correct

lukranit [14]

Answer:

See explanation

Step-by-step explanation:

You are given the equation of the curve

$y=\dfrac{x}{1+x}$

Point $P\left(1,\dfrac{1}{2}\right)$ lies on the curve.

Point $Q\left(x,\dfrac{x}{1+x}\right)$ is an arbitrary point on the curve.

The slope of the secant line PQ is

$\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\frac{x}{1+x}-\frac{1}{2}}{x-1}=\dfrac{\frac{2x-(1+x)}{2(x+1)}}{x-1}=\dfrac{\frac{2x-1-x}{2(x+1)}}{x-1}=\\ \\=\dfrac{\frac{x-1}{2(x+1)}}{x-1}=\dfrac{x-1}{2(x+1)}\cdot \dfrac{1}{x-1}=\dfrac{1}{2(x+1)}\ [\text{When}\ x\neq 1]$

1. If x=0.5, then the slope is

$\dfrac{1}{2(0.5+1)}=\dfrac{1}{3}\approx 0.3333$

2. If x=0.9, then the slope is

$\dfrac{1}{2(0.9+1)}=\dfrac{1}{3.8}\approx 0.2632$

3. If x=0.99, then the slope is

$\dfrac{1}{2(0.99+1)}=\dfrac{1}{3.98}\approx 0.2513$

4. If x=0.999, then the slope is

$\dfrac{1}{2(0.999+1)}=\dfrac{1}{3.998}\approx 0.2501$

5. If x=1.5, then the slope is

$\dfrac{1}{2(1.5+1)}=\dfrac{1}{5}\approx 0.2$

6. If x=1.1, then the slope is

$\dfrac{1}{2(1.1+1)}=\dfrac{1}{4.2}\approx 0.2381$

7. If x=1.01, then the slope is

$\dfrac{1}{2(1.01+1)}=\dfrac{1}{4.02}\approx 0.2488$

8. If x=1.001, then the slope is

$\dfrac{1}{2(1.001+1)}=\dfrac{1}{4.002}\approx 0.2499$

7 0

3 years ago

Determine if there is a proportional relationship between the two quantities

Shalnov [3]

Answer:

The table a not represent a proportional relationship between the two quantities

The table b represent a proportional relationship between the two quantities

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $k=\frac{y}{x}$ or $y=kx$

<u><em>Verify each table</em></u>

<em>Table a</em>

Let

A ----> the independent variable or input value

B ----> the dependent variable or output value

the value of k will be

$k=\frac{B}{A}$

For A=35, B=92 ---> $k=\frac{92}{35}=2.63$

For A=23, B=80 ---> $k=\frac{80}{23}=3.48$

the values of k are different

therefore

There is no proportional relationship between the two quantities

<em>Table b</em>

Let

C ----> the independent variable or input value

D ----> the dependent variable or output value

the value of k will be

$k=\frac{D}{C}$

For C=20, D=8 ---> $k=\frac{8}{20}=0.40$

For C=12.5, D=5 ---> $k=\frac{5}{12.5}=0.40$

the values of k are equal

therefore

There is a proportional relationship between the two quantities

The linear equation is equal to

$D=0.40C$

7 0

3 years ago

Estimate 5,403 divided by 94

VLD [36.1K]

Answer:

60

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers