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faust18 [17]
3 years ago
15

Helo please find the values of x and y ​

Mathematics
1 answer:
Dimas [21]3 years ago
3 0

Answer:

x=5

y=20

Step-by-step explanation:

abc =def

3X-3=12          

X=(12+3)\3 =5

AND    7X+Y=55

Y=20

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Answer:

  4·6 = 24 ≠ 12 = LCM(4, 6)

Step-by-step explanation:

Any pair of numbers with a common factor will refute Sarah's conjecture.

One such pair is 4 and 6, which have a product of 24. The LCM of 4 and 6 is 12, which is that product divided by their common factor of 2.

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a school netball team won ten matches , lost four and drew 1/8 of the total played . how many matches were drawn and what fracti
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The school net ball team drew 2 matches. The team won \frac{5}{8} of total matches played

<h3><u>Solution:</u></h3>

Given, A school netball team won ten matches, lost four and drew \frac{1}{8} of the total played

Let the total number of matches played be "n"

Number of matches drawn = \frac{1}{8} of n

<em>Total matches played = number of won matches + number of lost matches + number of drawn matches</em>

\begin{array}{l}{n=10+4+\frac{1}{8} n} \\\\ {n-\frac{1}{8} n=10+4}\end{array}

Taking "n" as common from left hand side,

\begin{array}{l}{\mathrm{n}\left(1-\frac{1}{8}\right)=14} \\\\ {\mathrm{n} \times \frac{8-1}{8} \quad 14} \\\\ {\mathrm{n} \times \frac{7}{8}=14} \\\\ {\mathrm{n}=16}\end{array}

So, they played 16 matches in total

Number of matches drawn = \frac{1}{8} of n = \frac{1}{8} \times 16 = 2\text { Fraction of won matches }=\frac{\text { number of matches won }}{\text { number of matches played }}=\frac{10}{16}=\frac{5}{8}

\text { Hence, the team drew } 2 \text { matches and won } \frac{5}{8} \text { of total played matches. }

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3 years ago
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