This is a right angle triangle problem
drawing a vertical line at from the point where the ramp touches the car park leaves a right angle triangle with the
opposite being 2m
hypothenus being 10m
adjacent unknown
we could use sine
SineO equal to opposite over hypothenus
SineO equal to 2/10
SineO equal to 0.2
O equal to Sine^1(0.2)
O equal to 11 .5
The angle between the ramp and the horizontal is 11.5 degrees
Answer:
1. -100
2. -75
3. -18
Step-by-step explanation:
Answer:
12√3
Step-by-step explanation:
well first divide 432 by 3
that gives you 144
so you have 144×3
you then but them both in radicals
144 is a perfect square i.e 12×12=144
3 isnt
therefore the answer is 12√3
Answer:
The solution of this system of equations is (3 , -8)
Step-by-step explanation:
The given system is
x + 2y = -13
12x + 5y = -4
We make x the subject of the first equation and put it into the second:
We put this expression for x into the second equation
12(-13-2y)+5y=-4
-156-24y+5y=-4
-24y+5y=-4+156
-19y=152
y=-8
We substitute y=-8 into x=-13-2y to get:
The solution of this system of equations is (3 , -8)
The slope-intercept form of 2x+y=8 is y=2x-8