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avanturin [10]
3 years ago
12

15. What's the area of the room in this diagram? A. 25 square feet B. 166 square feet C. 156 square feet D. 84 square feet

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
8 0

d is the answer' because it is :D



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(a) Suppose one house from the city will be selected at random. Use the histogram to estimate the probability that the selected
vodka [1.7K]

Answer:

a.    0.71

b.    0.9863

Step-by-step explanation:

a. From the histogram, the relative frequency of houses with a value less than 500,000 is 0.34 and 0.37

-#The probability can therefore be calculated as:

P(500000)=P(x=0)+P(x=500)\\\\\\\\=0.34+0.37\\\\\\\\=0.71

Hence, the probability of the house value being less than 500,000 is o.71

b.

-From the info provided, we calculate the mean=403 and the standard deviation is 278 The probability that the mean value of a sample of n=40 is less than 500000 can be calculated as below:

P(\bar X

Hence, the probability that the mean value of 40 randomly selected houses is less than 500,000 is 0.9863

8 0
4 years ago
Which of the following is the solution to | 17 x| > -17?
andreyandreev [35.5K]
All values are solution
5 0
3 years ago
Read 2 more answers
Find the midpoint of the line segment with end coordinates of:
Arisa [49]

Answer:

The midpoint of this line segment is (-1.5, -4.5).

Step-by-step explanation:

In finding the midpoint of a line segment we are actually averaging the x- and y-coordinates of the endpoints:

                                             -2 -1

x-coordinate of midpoint = --------- = -3/2 = -1.5

                                                 2

                                              -4 -5

y-coordinate of midpoint = ---------- = -4.5

                                                   2

The midpoint of this line segment is (-1.5, -4.5).

5 0
3 years ago
Which statement is true regarding the graphed functions?
padilas [110]

Answer:

C

Step-by-step explanation:

You can look them up in the graphs.

f(2) means "where is the blue graph when x=2?", and you can see it is at y=0.

4 0
3 years ago
Read 2 more answers
Let us analyze the following setting. You are given a circle of unit circumference. You pickkpoints on the circle independently
garik1379 [7]

Answer:

We have been given a unit circle which is cut at k different points to produce k different arcs. Now we can see firstly that the sum of lengths of all k arks is equal to the circumference:

\small \sum_{i = 1}^{k} L_i= 2\pi

Now consider the largest arc to have length \small l . And we represent all the other arcs to be some constant times this length.

we get :

 \small \sum_{i = 1}^{k} C_i.l = 2\pi

where C(i) is a constant coefficient obviously between 0 and 1.

\small \sum_{i = 1}^{k} C_i= 2\pi/l

All that I want to say by using this step is that after we choose the largest length (or any length for that matter) the other fractions appear according to the above summation constraint. [This step may even be avoided depending on how much precaution you wanna take when deriving a relation.]

So since there is no bias, and \small l may come out to be any value from [0 , 2π] with equal probability, the expected value is then defined as just the average value of all the samples.

We already know the sum so it is easy to compute the average :

\small L_{Exp} = \frac{2\pi}{k}

7 0
3 years ago
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