What should be added2x ^3+ 3x^2+8x-4to get 0 ?

Mathematics

1 answer:

lapo4ka [179]2 years ago

6 0

Answer:

-2x^3 - 3x^2 -8x + 4 should be added

Step-by-step explanation:

Here, we want to know what should be added to the expression to get 0

What we should do in this case is to simply negate the values we have in the expression already

Adding the negated values will give 0

So, we have that;

-2x^3 - 3x^2 -8x + 4

You might be interested in

Alinethatincludesthepoint(6, 3)hasaslopeof 2 . what isitsequationin slope -intercept form?

Marianna [84]

Hi Kay, the point-slope form of a line is given by: y - y1 = m(x - x1). Substituting the given point, (6, -8), and the slope, -2, gives: y - (-8) = -2 * (x - 6) This becomes: y + 8 = -2x + 12

3 0

2 years ago

What is (x^-2 y^10)^2/x^5 y^-3 using only positive exponents

Eddi Din [679]

Answer:

$\frac{(x^{ - 2}{y}^{10})^{2} }{ {x}^{5} {y}^{ - 3} } \\ \frac{ {x}^{ - 4} {y}^{20} }{ {x}^{5} {y}^{ - 3 } } \\ {x}^{ - 9} {y}^{23} \\ \frac{ {y}^{23} }{ {x}^{9} } \\ ans \: c$