Your answer will be 4,605,000
Answer:
distance formula attached...
it's approximately 8.6
Step-by-step explanation:
Answer:
-15a² -14a+16
Step-by-step explanation:
<h2>(2-3a)(8+5a)</h2>
2×8=16
2×5a=10a
-3a×8=-24a
-3a×5a=-15a²
16+10a-24a-15a² = -15a² -14a+16
I'm guessing these are regular polygons so... here goes.... 11. angle 1 is (8-2)*180= 1080 then divide that by 8 (how many angles there are ) to get 135. angle 2 is 360/8 (the sum of the exterior angle is always 360) which is 45 and multiply it by 2 (because the two polygons are stuck together) to get 90.
12. it says 2 squares so angle 4 is definitely 90. angles 3 and 5 would be 45 because it's an isosceles right triangle meaning that 1 angle is 90 and that the total of the other two angles would be 90 as a triangle angle sum is 180 and since it's isosceles just divide 90 by 2 because the 2 angles are the same getting 45for angles 3 and 5.
13. the triangle includes 2 exterior angles so...360 divided by 8 = 45 (this is the measure of each exterior angle of the polygon)
45 x 2 cause as I said it includes 2 exterior angles to get 90. it's a triangle so 180 (the sum of angles in triangle) minus 90 to get 90. so 1 and 2 are both 45 and 3 is 90
Answers:
Functions
- y = -x+11
- y = 2x^2-6x+4
- y = -7
Not functions
- x = 3
- x^2+y^2 = 81
- y^2 = -5x-12
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Explanation:
A function is possible if and only if any given x input leads to exactly one y output.
For something like x^2+y^2 = 81, we can see that x = 0 leads to either y = 9 or y = -9. So this would <u>not</u> be a function. We would need x to pair with only y value to have it be a function.
We have the same thing going on with y^2 = -5x-12 as well.
For anything of the form x = k, where k is any real number, this is also not a function. We have one single input only and it leads to infinitely many outputs. So in a sense, this is even worse compared to the other examples.
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In summary, we have these three non-functions:
- x = 3
- x^2+y^2 = 81
- y^2 = -5x-12
Everything else is a function. You can use the vertical line test as a visual way to check.