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Flauer [41]
4 years ago
7

What greatest three digit number whose hundreds is two less than its ones digit

Mathematics
1 answer:
kodGreya [7K]4 years ago
4 0

Answer:

799

Step-by-step explanation:

Let x = the hundreds digit

Let y = the ones digit

x = y-2

We want to maximize x and y.  The both have to be single digit numbers

Rewriting this

x+2 =y

The largest x can be is 7 if y is a single digit

x is 7 and y is 9

We can pick the tens digit.  Make it as big as possible to make out number as large as possible

799

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Answer:

Juanita dissolves 46 g of MgBr2 (molar mass: 184.11 g/mol) in 0.5 kg of distilled water. What is the molality of the solution?

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28 + 7x = 16
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3 years ago
NEED HELP ASAP!!
devlian [24]

Answer:we multiply by the reciprocal of a fraction when completing a division problem because it is a rule in mathematics that when you divide two fraction, you change the division sign to multiplication and flip the fraction at the right of the multiplication sign.

Step-by-step explanation:

For example if you have 4÷ 1/2. It basically means how many 1/2 can one get in 4. And the answers is 8.

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4 0
3 years ago
Can someone help me please ​
andrey2020 [161]

Answer: y = 6

Step-by-step explanation:

A square's area can be done by using s^2, where s is y in this case.  Because there are 5 squares, the area of the figure is 5y^2.  Because the area is also 180cm, 5y^2=180.

Then divide both sides of the equation by 5 to get y^2 = 36.  Then square root both sides of the equation to get y = 6.

Hope it helps <3

7 0
3 years ago
Find the annual rate of interest. Principal = 4600 rupees, Period = 5 years, Total amount = 6440 rupees, Annual rate of interest
Len [333]

The annual rate of interest per year is 8%

<u>Solution:</u>

Given:- Principal (p) = 4600 rupees, Time –Period (t) = 5 years, Total amount(A) = 6440 rupees

First we will calculate the Interest and then using formula of simple interest we will calculate the rate of interest

Interest = Amount – Principal

Interest = 6440  – 4600 = 1840

Now using the formula of simple Interest and on putting values we get,

\text {Simple Interest }=\frac{P \times R \times T}{100}

Where "P" is the principal and "R" is the rate of interest per annum and "T" is the time period

1840=\frac{4600 \times R \times 5}{100}

\begin{aligned} \mathrm{R} &=\frac{1840 \times 100}{4600 \times 5} \\\\ \mathrm{R} &=\frac{1840}{230} \\\\ \mathrm{R} &=8 \% \end{aligned}

Hence, the required rate of interest per year is 8%

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3 years ago
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