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3 years ago

Round 981,657 to the nearest ten thousand

Mathematics

1 answer:

MaRussiya [10]3 years ago

5 0

981,657 = 980,000 to the nearest ten thousand

Hope it helps

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Evaluate 14 + (-8) ÷ 2 · -3. -9 15 26 -30

Rudiy27

For this case we must evaluate the following expression:

14 + (- 8) ÷ 2 * -3

According to the method of algebraic resolution, called PEMDAS, the divisions and multiplications must be made from left to right, before the addition and subtraction, then:

14 + (- 4) * - 3 =

We eliminate the parenthesis keeping in mind that $- * - = +$

$14 + 12 =$

Equal signs are added and the same sign is placed:

$14 + 12 = 26$

Answer:

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3 years ago

I just started learning about rate and I am stuck on a question.(A watch keeps perfect time but only has an hour hand. If the ho

8090 [49]

Answer:

36 minutes past 1, or 1:36

Step-by-step explanation:

A watch normally has an hour hand that does one revolution in 12 hours.

It takes 1 hour to go from the 1 o'clock position to the 2 o'clock position.

Since 1 hour equals 60 minutes, it takes 60 minutes to go from the 1 o'clock position to the 2 o'clock position.

The hour hand is 3/5 of the way from 1 to 2, so the number of minutes past 1 o'clock is 3/5 of 60 minutes.

3/5 of 60 minutes =

= 3/5 * 60 minutes

= 3/5 * 60/1 minutes

= 180/5 minutes

= 36 minutes

The time is 36 minutes past 1, or 1:36

7 0

3 years ago

A jar contains 3 red, 2 white, and 1 green marble. Aside from color, the marbles are indistinguishable. Two marbles are drawn at

IRISSAK [1]

Answer:

0.6

Step-by-step explanation:

A permutation is an arrangement of outcomes whereas a combination is a grouping of outcomes.

Order matters in case of permutations but does not matter in combinations.

Given:

Number of red marbles = 3

Number of white marbles = 2

Number of green marbles = 1

To find: probability of picking 4 marbles and getting one of each color

Solution:

Total number of outcomes = $6_C__4$ = $\frac{6!}{4!\,2!}=\frac{6\times 5\times 4!}{4!\times 2}=15$

Number of favourable outcomes = 2 red, 1 white and 1 green marble + 1 red, 2 white and 1 green marble = $3_C_2\,2_C_1\,1_C_1+3_C_1\,2_C_2\,1_C_1$ = $\frac{3!}{2!\,1!}\times \frac{2!}{1!\,1!}\times 1+\frac{3!}{2!\,1!}\times 1\times 1=6+3=9$

So, probability of picking 4 marbles and getting one of each color = Number of favourable outcomes/Total number of outcomes = $\frac{9}{15}=\frac{3}{5}=0.6$