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Vinil7 [7]
3 years ago
12

What is the total number of atoms in the formula below? NH3

Physics
2 answers:
slavikrds [6]3 years ago
6 0

The answer is 4 because N=1 and H3

GrogVix [38]3 years ago
6 0

The total number of atoms in the ammonia is four.

<u>Explanation:</u>

The chemical formula for ammonia is \mathrm{N} \mathrm{H}_{3} which has one atom of nitrogen with 3 atoms of hydrogen. The number of atom is counted from the chemical formula itself.  

As there is one N shown so there will be one atom of nitrogen. Then there is H is shown with 3 subscript, so there is 3 atom of hydrogen.  Therefore,

1 atom of nitrogen + 3 atom of hydrogen = 4 atoms in ammonia.

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25 times the average speed

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Which type of bond is found between the atoms of a molecule?
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Covalent Bond is found between the atoms of a molecule.

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Turning a corner at a typical large intersection in a city means driving your car through a circular arc with a radius of about
Naddik [55]

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9.89 m/s.

Explanation:

Given that,

The radius of the circular arc, r = 25 m

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Let v is the maximum speed at which you should drive through this turn. It can be solved as follows :

a=\dfrac{v^2}{r}\\\\v=\sqrt{ar} \\\\v=\sqrt{3.92\times 25} \\\\=9.89 m/s

So, the maximum speed of the car should be 9.89 m/s.

8 0
3 years ago
A 140 g baseball is moving horizontally to the right at 35 mis when it is hit by the bat. the ball fl ies off to the le ft at 55
Anit [1.1K]

Answer:

J = 12.32kg*m/s

Explanation:

Assumptions: I'm assuming mis is m/s

Given: The baseball's mass is 140g, so convert to kg, 0.140kg. (Good rule of thumb, in physics convert grams to kilograms). It is initially traveling 35 m/s to the right.

When it hits the bat, it flies left with a velocity of 55 m/s at an angle of 25°. To reiterate:

mass = 0.140kg, Initial: 35m/s, Final: 55m/s at an angle of 25°

For this problem, we have to use the impulse equation, but before that lets break the velocity into components (It will be apparent towards the end):

The initial velocity is moving only in the horizontal direction, so:

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The final velocity has an x and a y component:

v_{fx} = 55cos(25) = 49.84692829m/s\\v_{fy} = 55sin(25) = 23.2440044m/s

Now the equation for impulse is (dp is Δp, which is difference in momentum; dv is Δv, the difference in velocity; J is impulse):

J = dp= m*dv

To get Δv, we have to find the difference of velocity, that is why we broke it into components. I'm going to define right as positive and left as negative. After that, we find the velocity vector:

dv_{x} = (35-(-49.84692829)) = 84.84692829 m/s\\dv_{y} = (0-(23.2440044)) = -23.2440044 m/s\\dv = \sqrt{(84.84692829)^2+(-23.2440044)^2} = 87.97320604m/s

Finally, substitute into the equation

J = m*dv\\J = 0.140kg * 87.97320604m/s\\J = 12.31624885kg*m/s\\J = 12.32 kg*m/s

J = 12.32kg*m/s

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