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madam [21]
3 years ago
14

The average radius of Mars is 3,397 km. If Mars completes one rotation in 24.6 hours, what is the tangential speed of objects on

the planet’s surface? Round your answer to the nearest whole number.
Physics
2 answers:
choli [55]3 years ago
7 1

Answer:

25 times the average speed

Allisa [31]3 years ago
6 0

Answer:

Tangential speed of objects on the planet’s surface = 241 m/s

Explanation:

Speed is given by the ratio of distance traveled to the time.

Radius of mars, r = 3397 km = 3.397 x 10⁶ m

Distance traveled = 2πr = 2 x π x 3.397 x 10⁶ = 2.13 x 10⁷ m

Time taken = 24.6 hours = 24.6 x 60 x 60 = 88560 s

\texttt{Tangential speed =}\frac{2.13\times 10^7}{88560}=240.51m/s

Tangential speed of objects on the planet’s surface = 240.51 m/s = 241 m/s

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Airida [17]

Answer:

735N

Explanation:

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3 years ago
Ice skaters often end their performances with spin turns, where they spin very fast about their center of mass with their arms f
vampirchik [111]

Answer:

\large \boxed{\text{30 rev/s}}

Explanation:

This question is based on the Law of Conservation of Angular Momentum.

Angular momentum (L) equals the moment of inertia (I) times the angular speed (ω).

L = Iω

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Data:

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Calculation:

\begin{array}{rcl}I_{1}\omega_{1} &= &I_{2}\omega_{2}\\\text{3.5 kg$\cdot$m$^{2}$}\times \text{6.0 rev/s} &= &\text{0.70 kg$\cdot$m$^{2}$}\times\omega_{2}\\\text{21 rev/s} &= &0.70\omega_{2}\\\omega_{2} & = & \dfrac{\text{21 rev/s}}{0.70}\\\\&=&\textbf{30 rev/s}\\\end{array}\\\text{The skater's final rotational speed is $\large \boxed{\textbf{30 rev/s}}$}

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4 years ago
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3 years ago
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OlgaM077 [116]

Answer:

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