Answer:
Tangential speed of objects on the planet’s surface = 241 m/s
Explanation:
Speed is given by the ratio of distance traveled to the time.
Radius of mars, r = 3397 km = 3.397 x 10⁶ m
Distance traveled = 2πr = 2 x π x 3.397 x 10⁶ = 2.13 x 10⁷ m
Time taken = 24.6 hours = 24.6 x 60 x 60 = 88560 s
Tangential speed of objects on the planet’s surface = 240.51 m/s = 241 m/s
Answer:
d) It will be cut to a fourth of the original force.
Explanation:
The magnitude of the electrostatic force between the charged objects is
where
k is the Coulomb's constant
q1 and q2 are the charges of the two objects
r is the separation between the two objects
In this problem, the initial distance is doubled, so
r' = 2r
Therefore, the new electrostatic force will be
So, the force will be cut to 1/4 of the original value.
Answer:
R = 1.2295 10⁵ m
Explanation:
After reading your problem they give us the diameter of the lens d = 4.50 cm = 0.0450 m, therefore if we use the Rayleigh criterion for the resolution in the diffraction phenomenon, we have that the minimum separation occurs in the first minimum of diffraction of one of the bodies m = 1 coincides with the central maximum of the other body
θ = 1.22 λ / D
where the constant 1.22 leaves the resolution in polar coordinates and D is the lens aperture
how angles are measured in radians
θ = y / R
where y is the separation of the two bodies (bulbs) y = 2 m and R the distance from the bulbs to the lens
R =
let's calculate
R =
R = 1.2295 10⁵ m