Weight of body = 35 lbs
F = ma
m = F/a = 35/32 ( acceleration = 32 ft/s^2)
m= 1.09
so again using same formula,
a = F/m
a= 6/1.09
a= 5.489
or say, acceleration = 5.5 ft/s^2 !!
Answer:
10 days
Explanation:
The half-life of a radioactive sample is the time taken for half of the sample to decay.
In the diagram, the half-life corresponds to the time after which the % of cobalt-57 has halved. We can observe the following:
At t=10 days, the % of Co remaining is approximately 45%
At t=20 days, the % of Co remaining is approximately 22%
This means that the sample of cobalt-57 has halved in 10 days, so the half-life of cobalt-57 is 10 days.
Answer:
20min = 20 × 60 = 1200sec.
Speed in m per sec.
V = 1000/1200
V = 0.833m per sec.
Explanation:
Answer: B) exactly the same as the initial momentum.
Explanation:
An inelastic collision occurs when the elements that collide remain together after the collision, and althogh the kinetic energy is not conserved because is transformed into other kinds of energy (thermal energy, for example), the linear momentum does.
This means the initial momentum before the collision will be equal to the final momentum after the collision:
Answer:
Question
Explanation:
The independent variable in Part I, the one that is intentionally manipulated, is the
.
The independent variable in Part II, the one that is intentionally manipulated, is the
.
The independent variable in Part III, the one that is intentionally manipulated, is the
.
The independent variable in Part IV, the one that is intentionally manipulated, is the
.