Answer:
The box will be moving at 0.45m/s. The solution to this problem requires the knowledge and application of newtons second law of motion and the knowledge of linear motion. The vertical component of the force Fp acts vertically upwards against the directio of motion. This causes a constant upward force of 23sin45° to act on the box. Fhe frictional force of 13N also acts vertically upwards and so two forces act upwards against rhe force of gravity resulting un a net force of 0.7N acting kn the box. This corresponds to an acceleration of 0.225m/s². So in w.0s after i start to push v = 0.45m/s.
Explanation:
Thunderstorms might form on warm days simply because heat is what causes evaporation, causing rain. Thunderstorms also form when the atmosphere is unstable! Meaning the hot air is above the cold air, evaporation occurs, it rains, and then rapid expansion of heat in the air caused by lighting causes thunder.
Answer:
F=523712 N
Explanation:
density=mass/volume
and shape is cubic so
volume=(4)^3
volume=64 m^3
mass=835*64
mass=53440 Kg
Hydrostatic force=53440*9.8=523712 N
If you look it up in Google or you read your textbook! it says the same thing almost, that Convex Mirror can only form virtual images, Only a Concave mirror can produce real images.
Answer:
ΔF = 0.21 N
Explanation:
For this exercise that does not ask for the change in weight we must use the law of universal gravitation
F = G M m / r²
where r is the distance from the center of the Earth, in the lower part of the building is
r =
for the upper part of the building h = 1 mile = 1609.34 m
r =R_{e} + h
the weight or the force of attraction of gravity on the floor is F = 817 N, therefore the equation remains
817 = (G M m / R_{e}²)
let's find this force for the top of the building
F` = G M m / (R_{e} + h)²
let's take out R_{e} common factor
F ’= (G M m / R_{e}²) 1 / (1 + h / R_{e})²2
F ’= (G M m R_{e}²) (1 + h / R_{e})⁻²
as the quantity h /R_{e} = 1609 / 6.37 10⁶ << 1 we can make a series space
(1 + x)⁻² = 1 -2 x + ...
we substitute
F ’= (GMm /R_{e}²) (1 - 2 1609 / 6.37 10⁶)
F ’= (GMm /R_{e}²) (1 - 2.53 10⁻⁴) = (GMm / R_{e}²) 0.99974
F ’= 817 0.99974
F ’= 816.79 N
weight Change
ΔF = ΔW = 817 - 816.79
ΔF = 0.21 N
as we see this is a very small amount