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3 years ago

Given 4x - y = 32, find: a.) x-intercept b.) y-intercept c.) slope

1 answer:

8 0

You always want to get y by itself and in the form y = mx + b. So first, subtract 4x from both sides to get -y = -4x +32
You also want to get rid of that negative sign. That’s easy, divide everything by negative 1 to get:
y = 4x - 32

We can see the slope is just 4 and the y intercept is -32. The y-intercept is when x equals zero, you’ll get -32 if you do so. The x-intercept is now when y equals zero. Now solve for x. You get 4x = 32, divide by 4 to get 8

a.) 8
b.) -32
c.) 4

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Describe the location of the point having the following coordinates. positive abscissa, positive ordinate Quadrant I Quadrant II

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The abscissa is the x coordinate whereas the ordinate is the y coordinate. Both x and y are positive in the first quadrant only.

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3 years ago

Brainliest for correct answer<br><br> A. 2<br><br> B. -2<br><br> C. 1/2<br><br> D. -1/2

seropon [69]

Answer:

B) -2

Step-by-step explanation:

I got the slope by using two points on the line (0,7) and (4,-1)

Slope=y2-y1/x2-x1

(7--1)/(0-4)

8/-4

I then simplified 8/-4 to -2

You could also solve by finding the rise over run for two points on the line.

The rise is 2 and the run is -1, making it 2/-1 or -2

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x and y are integers between 0 and 10 that satisfy the equation shown below. x2=y⎯⎯√+3 What values for x and y satisfy the equat

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3 years ago

What makes this bond correct <br> 3/4+__=2<br> WHATS THE ANSWER

VladimirAG [237]

Answer:

The answer is 5/6.

Step-by-step explanation:

Lets start with a=1.

a+1=2, which is the denominator. (1/2)

Taking the same number as numerator, now, consider a=2.

a+1=3, denominator.(2/3)

Now, let a=3.

a+1==4, denominator for a=3. (3/4)

If continued a becomes equal to 4.

a+1=5, which is also the denominator. (4/5)

Now, since the denominator is 5, let a=5.

a+1=6, which will become the denominator. (5/6)

Thus the series follows a pattern of a/a+1.

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3 years ago

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A football is thrown from the top of the stands, 50 feet above the ground at an initial velocity of 62 ft/sec and at an angle of

Anvisha [2.4K]

a. i. The parametric equation for the horizontal movement is x = 43.84t

ii. The parametric equation for the vertical movement is y = 50 + 43.84t

b. the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

<h2>a. Parametric equations</h2>

A parametric equation is an equation that defines a set of quantities a functions of one or more independent variables called parameters.

<h3>i. Parametric equation for the horizontal movement</h3>

The parametric equation for the horizontal movement is x = 43.84t

Since

the angle of elevation is Ф = 45° and
the initial velocity, v = 62 ft/s,

the horizontal component of the velocity is v' = vcosФ.

So, the horizontal distance the football moves in time, t is x = vcosФt

= vtcosФ

= 62tcos45°

= 62t × 0.7071

= 43.84t

So, the parametric equation for the horizontal movement is x = 43.84t

<h3>ii Parametric equation for the vertical movement</h3>

The parametric equation for the vertical movement is y = 50 + 43.84t

Also, since

the angle of elevation is Ф = 45° and
the initial velocity, v = 62 ft/s,

the vertical component of the velocity is v" = vsinФ.

Since the football is initially at a height of h = 50 feet, the vertical distance the football moves in time, t relative to the ground is y = 50 + vsinФt

= 50 + vtcosФ

= 50 + 62tsin45°

= 50 + 62t × 0.7071

= 50 + 43.84t

<h3>b. Location of football at maximum height relative to starting point</h3>

The location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Since the football reaches maximum height at t = 1.37 s

The x coordinate of its location at maximum height is gotten by substituting t = 1.37 into x = 48.84t

So, x = 43.84t

x = 43.84 × 1.37

x = 60.0608

x ≅ 60.1 ft

The y coordinate of the football's location at maximum height relative to the ground is y = 50 + 48.84t

The y coordinate of the football's location at maximum height relative to the starting point is y - 50 = 48.84t

So, y - 50 = 48.84t

y - 50 = 43.84 × 1.37

y - 50 = 60.0608

y - 50 ≅ 60.1 ft

So, the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Learn ore about parametric equations here:

brainly.com/question/8674159

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2 years ago