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ch4aika [34]
3 years ago
5

The pair of points is on the graph of an inverse variation. Find the missing value.

Mathematics
2 answers:
Ivanshal [37]3 years ago
6 0

Answer:

1.2

Step-by-step explanation:


LiRa [457]3 years ago
5 0
The x-value increases by a factor of 5 from 1.6 to 8 between the two points. Because the variation is inverse, the y-value must decrease by a factor of 5 between the two points.

6/5 = 1.2

The second point is (8, 1.2), corresponding to the 4th selection.

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If (8^9)p = 8^18, what is the value of p? (4 points)<br><br> 2<br> 9<br> 10<br> 18
EleoNora [17]

Answer:

p is 2.

Step-by-step explanation:

6 0
3 years ago
6) What is the Converse of the following
Sladkaya [172]

Answer:

B) If you don't do you homework, then you can't go to the movies

3 0
2 years ago
what is the acceleration of a baseball when its speed increases from 1 m/sec to 25 m/sec in 1 second?
kirill115 [55]

Answer:

24 m/s²

Step-by-step explanation:

Acceleration is change in velocity over time.

a = Δv / Δt

a = (25 m/s − 1 m/s) / 1 s

a = 24 m/s²

7 0
3 years ago
One technique of killing cancer cells involves inserting microscopic synthetic rods, called carbon nanotubules, into the cell. W
Vlad [161]

Answer:

The probability that the cell will be killed is 0.9328.

Step-by-step explanation:

We are given that five nanotubules are inserted in a single cancer cell. Independently of each other, they become exposed to near-infrared light with probabilities 0.2, 0.4, 0.3, 0.6, and 0.5.

Let the event that a cell is killed be 'A' and the event where the ith nanotubule kill the cell be '\text{B}_i'.

This means that the cell will get killed if \text{B}_1 \bigcup \text{B}_2 \bigcup \text{B}_3 \bigcup \text{B}_4 \bigcup \text{B}_5 happens. This represents that the cell is killed if nanotubule 1 kills the cell, or nanotubule 2 kills the cell, and so on.

Here, P(\text{B}_1) = 0.2, P(\text{B}_2) = 0.4, P(\text{B}_3) = 0.3, P(\text{B}_4) = 0.6, P(\text{B}_5) = 0.5.

So, the probability that the cell will be killed is given by;

P(A)= 1 - [(1 - P(\text{B}_1)) \times (1 - P(\text{B}_2)) \times (1 - P(\text{B}_3)) \times (1 - P(\text{B}_4)) \times (1 - P(\text{B}_5))]

P(A) = 1 - [(1 - 0.2) \times (1 - 0.4) \times (1 - 0.3) \times (1 - 0.6) \times (1 - 0.5)]

P(A) = 1 - (0.8 \times 0.6 \times 0.7 \times 0.4 \times 0.5)

P(A) = 1 - 0.0672 = 0.9328

Hence, the probability that the cell will be killed is 0.9328.

4 0
3 years ago
Yo, can u help me with this, please?​
GarryVolchara [31]

Answer:

it is 12

Step-by-step explanation:

8 0
3 years ago
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