Answer:

Step-by-step explanation:
here's the solution :-
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Given conditions are :
In 1980's, a typical middle-income household earned= $34,757
In 2009, a similar middle-income household earned= $38,550
And we have to find relative increase in income for these households from 1980 to 2009.
So first we will find the total increase in amounts.

Relative increase = 
= 10.91% or rounding it off we get approx 11%.
Hence, the answer is 11%.
9514 1404 393
Answer:
19. B -- continued, but modest ...
Step-by-step explanation:
19. There is no decline or decrease indicated on this graph. If growth were exponential, the graph would be concave upward, which it is not. There is continued growth indicated.
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20. The percentage change from 2005 to 2010 is ...
(60 -20)/20 × 100% = 2 × 100% = 200%
One might compute an average rate of change per year of ...
200%/(5 yr) = 40%/yr
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<em>Additional comment</em>
As with any statement of percentage, you need to be very clear about what the base is.
Here, 100% is the number of farms in 2005, so an increase of 40% per year is an increase by 40% of the number in 2005. That is very different from 40% of the number in the previous year, which is how an annual percentage increase is usually interpreted. (The average annual rate of change is closer to 24% with respect to the previous year's number.)
Answer: The numbers are decreasing by 2. So that means that the eighteenth number would be -29.
Explanation:
{5, 3, 1, -1, -3, -5, -7, -9, -11, -13, -15, -17, -19, -21, -23, -25, -27, -29...}
Answer: A. 1
Step-by-step explanation:
sorry if im wrong