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Finger [1]
4 years ago
14

You walk into an elevator, step onto a scale, and push the "down" button to go directly from the tenth floor to the first floor.

You also recall that your normal weight is w= 635 N. If the elevator has an initial acceleration of magnitude 2.45 m/s2, what does the scale read? Express your answer in newtons.

Physics
2 answers:
Alenkasestr [34]4 years ago
8 0

Answer: 479. 425 N

Explanation: the calculation of a body in an elevator obeys Newton law. When it is accelerating upward, the scale reading is greater than the true weight of the person.

It is given by N= m(g+a)

When it is accelerating downward, the scale reading is less than the true weight.

It so given by N = m(g-a)

The answer to the above questions is in the attached photo

Vsevolod [243]4 years ago
8 0

Answer:

<em>the scale will read 476.414 N</em>

<em></em>

Explanation:

Weight = 635 N

mass = (weight) ÷ (acceleration due to gravity 9.81 m/^2)

mass m = 635 ÷ 9.81 = 64.729 kg

initial acceleration of the elevator a = 2.45 m/s^2

<em>the force produced by the acceleration of the elevator downwards = ma</em>

<em>your body inertia force try to counteract this force, by a force equal and opposite to the direction of this force, leading to an apparent weight loss</em>

apparent weight = weight - ma

apparent weight = 635 - (64.729 x 2.45)

apparent weight =  635 - 158.586  = <em>476.414 N</em>

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