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Lena [83]
2 years ago
12

Now that you know how forces affect the motions of objects, you can use the Tracker video analysis tool to create dynamic models

Physics
1 answer:
rodikova [14]2 years ago
4 0

Answer:

Now that you know how forces affect the motions of objects, you can use the Tracker video analysis tool to create dynamic models

for a wide range of physical situations.

Tracker enables you to create two different types of mathematical models: analytical and dynamic. An analytical model enables you

to enter mathematical expressions for x and y positions as a function of time. That's sometimes useful, but from a physics

perspective, a dynamic model is much more flexible and powerful.

A dynamic model enables you to set the initial conditions for a particular system (Initial positions and velocities); then you can

mathematically define any forces acting on that system. Once those are set up, the model acts like an object in space, responding to

the forces you've imposed on it. It can continue moving forever, if that's what the forces would do to an object in real life. By visually

matching a marker for your model to the real motion on the video, you can define and refine a mathematical model for a

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julsineya [31]

0.05*0.2=0.05*0.15+0.015*m2',

m2'=1/6 m/s,

m2'=0.17 m/s

N I C E - D A Y!

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3 years ago
Which factor indicates the amount of charge on the source charge?
Elina [12.6K]
B. The number of field lines on the source charge.
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A 50-g cube of ice, initially at 0.0°C, is dropped into 200 g of water in an 80-g aluminum container, both initially at 30°C.
MakcuM [25]

Answer:

b. 9.5°C

Explanation:

m_i = Mass of ice = 50 g

T_i = Initial temperature of water and Aluminum = 30°C

L_f = Latent heat of fusion = 3.33\times 10^5\ J/kg^{\circ}C

m_w = Mass of water = 200 g

c_w = Specific heat of water = 4186 J/kg⋅°C

m_{Al} = Mass of Aluminum = 80 g

c_{Al} = Specific heat of Aluminum = 900 J/kg⋅°C

The equation of the system's heat exchange is given by

m_i(L_f+c_wT)+m_wc_w(T-T_i)+m_{Al}c_{Al}=0\\\Rightarrow 0.05\times (3.33\times 10^5+4186\times T)+0.2\times 4186(T-30)+0.08\times 900(T-30)=0\\\Rightarrow 1118.5T-10626=0\\\Rightarrow T=\dfrac{10626}{1118.5}\\\Rightarrow T=9.50022\ ^{\circ}C

The final equilibrium temperature is 9.50022°C

4 0
3 years ago
A car has a mass of 1600 kg. It is stuck in the snow and is being pulled out by a cable that applies a force of 7560 N due north
sergiy2304 [10]

Answer:

Acceleration of the car will be a=0.1375m/sec^2

Explanation:

We have given mass of the ball m = 1600 kg

Force in north direction F= 7560 N

Resistance force which opposes the movement of car F_R=7340N

So net force on the car F_{net}=F-F_R=7560-7340=220N

According to second law of motion we know that F=ma

So 220=1600\times a

a=0.1375m/sec^2

7 0
3 years ago
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