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2 years ago

Now that you know how forces affect the motions of objects, you can use the Tracker video analysis tool to create dynamic models

Physics

1 answer:

rodikova [14]2 years ago

4 0

Answer:

Now that you know how forces affect the motions of objects, you can use the Tracker video analysis tool to create dynamic models

for a wide range of physical situations.

Tracker enables you to create two different types of mathematical models: analytical and dynamic. An analytical model enables you

to enter mathematical expressions for x and y positions as a function of time. That's sometimes useful, but from a physics

perspective, a dynamic model is much more flexible and powerful.

A dynamic model enables you to set the initial conditions for a particular system (Initial positions and velocities); then you can

mathematically define any forces acting on that system. Once those are set up, the model acts like an object in space, responding to

the forces you've imposed on it. It can continue moving forever, if that's what the forces would do to an object in real life. By visually

matching a marker for your model to the real motion on the video, you can define and refine a mathematical model for a

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An ultrasound unit is being used to measure a patient's heartbeat by combining the emitted 2.0 MHz signal with the sound waves r

alexandr402 [8]

Hi there,
for this question we have:
Signal 2.0 MHz = Emitted so we can call it $f_e$
and we need the Reflected = $f_{r}$
In this question, we have a source which goes to the heart and a reflected which comes back from the heart and we need the speed of the reflected.
So you should know that the speed of reflected is lower than the source(Emitted).
we also know: ΔBeat frequency(max) = 560 Hz = $f_{b}$
so we have:
$f_{e}$ - $f_{r}$ = $f_{b}$
so frequency of Reflected is:
2.0 × 10^6 Hz - 560 Hz = 1.99 × 10^6 Hz = $f_{r}$
now you know that Lambda = v/f
so if we find the lambda with our Emitted then we can find v with the Reflected:
Lambda = 1540(m/s) / 2.0 × 10^6 Hz = 7.7 × 10^-4 m
=> $v_{max}$ = (lambda)( $f_{r}$
=> 7.7 × 10^-4m (1.99 × 10^6Hz) = 1532 m/s
so the $v_{max}$ is equal to 1532 m/s :)))
This question is solved by two top teachers as fast as they could :))
I hope this is helpful
have a nice day

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3 years ago

Easy defimation of newtons second law of motion

shtirl [24]

Hi pupil here's your answer ::

_______________________________

Newton's Second Law of motion states that the rate of change of momentum of an object is proportional to the applied unbalanced force in the direction of the force.
ie., F=ma

Where F is the force applied, m is the mass of the body, and a, the acceleration produced.

Or in simplest language it is the force applied to a particular object of particular mass multiplied by the acceleration caused by force .

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hope that it helps. . . . . .

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