Answer:
F=2.589×10⁻⁷ Newtons
Explanation:
The gravitational force of attraction between two bodies is given by
F= Gm₁m₂/r²
Where m₁ and m₂ are the masses of the two bodies, G is the universal gravitational constant while r is the distance between the two bodies.
G=6.67408 × 10⁻¹¹m³kg⁻¹s⁻²
r=1.15m
m₁=75.0kg
m₂=68.4kg
Therefore F= (6.67408×10⁻¹¹m³kg⁻¹s⁻²×75.0kg×68.4kg)/(1.15m)²
F=2.589×10⁻⁷ Newtons
Answer:
distance = 27.95 [mi]
Explanation:
in order to solve this problem, we must use the appropriate conversion factor, i.e. a conversion factor that relates the kilometers to Miles.
![1 [km] = 0.6214 [mill]\\45[km]*0.6212[\frac{mill}{1km} ]=27.95 [mill]](https://tex.z-dn.net/?f=1%20%5Bkm%5D%20%3D%200.6214%20%5Bmill%5D%5C%5C45%5Bkm%5D%2A0.6212%5B%5Cfrac%7Bmill%7D%7B1km%7D%20%5D%3D27.95%20%5Bmill%5D)
Hello there
<span>0.00432 km =4320mm
Answer. </span>4320
I am 11 year old and I don't known the answer to this question
10.7 rad/s is the final angular velocity of the stick.
Given:
Mass of the stick = 4.42 kg
Length of the stick = 1.23m
Force of impulse (I) = 12.8 N s
The linear velocity of the stick, 


Therefore, the final linear velocity of the stick is 2.89 m/s
∴



Therefore, 10.7 rad/s is the final angular velocity of the stick.
Learn more about linear velocity here:
brainly.com/question/15154527
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