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LekaFEV [45]
3 years ago
8

Which expression both gives the average rate of change of the function h(x)

Mathematics
1 answer:
liubo4ka [24]3 years ago
5 0

Answer:

D

Step-by-step explanation:

The average rate of change of a function over an interval a ≤ x ≤ b is found by:

\frac{f(b)-f(a)}{b-a}

Here, a is 0 and b is 3, so: \frac{f(3)-f(0)}{3-0}=\frac{f(3)-f(0)}{3}

Just plug in 3 for the first term and 0 for the second term in the numerator:

- First term: \frac{1}{2} (3^{3+\frac{1}{2} })+3=\frac{1}{2} (3^{3\frac{1}{2} })+3

- Second term: \frac{1}{2} (3^{0+\frac{1}{2} })+3=\frac{1}{2} (3^{\frac{1}{2} })+3

So, the final answer is:

\frac{[\frac{1}{2} (3^{3\frac{1}{2} })+3]-[\frac{1}{2} (3^{\frac{1}{2} })+3]}{3}

Thus, the answer is D.

Hope this helps!

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