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slega [8]
3 years ago
11

Generate two numerical patterns

Mathematics
1 answer:
Klio2033 [76]3 years ago
8 0

Answer:

vvv

Step-by-step explanation:

2,4,6,8,10

Pattern Rule:Add 2

1,2,4,8,16

Pattern:Multiply by 2

Sorry these were simple.

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24,12,6,...<br>find the 8th term.<br>​
weeeeeb [17]

Answer:

a = 24

r = 1/2

<h3>8th term = ar^(n-1)</h3><h3> = 24. (1/2)^-1/2</h3>
8 0
3 years ago
Choose the numerical expression that represents multiplying the sum of 159 and 833 by 6​
Eva8 [605]

Answer:

(159+833)*6 = 5952

Step-by-step explanation:

(159 + 833) * 6

= 992*6 = 5952

4 0
3 years ago
Adair needs $21,150 to purchase a boat. How much money will you need to invest today in a savings account earning 3.2% interest,
emmasim [6.3K]
A=x(1+r/n)^nt
21150=x(1+0.032/12)^84
21150=x(1+0.0026666)^84
21150=x(1.002666666)^84
21150=x(1.25069809)
21150/1.25069809=x
16910.56=x

Hope this helps!
8 0
4 years ago
Use stoke's theorem to evaluate∬m(∇×f)⋅ds where m is the hemisphere x^2+y^2+z^2=9, x≥0, with the normal in the direction of the
ludmilkaskok [199]
By Stokes' theorem,

\displaystyle\int_{\partial\mathcal M}\mathbf f\cdot\mathrm d\mathbf r=\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S

where \mathcal C is the circular boundary of the hemisphere \mathcal M in the y-z plane. We can parameterize the boundary via the "standard" choice of polar coordinates, setting

\mathbf r(t)=\langle 0,3\cos t,3\sin t\rangle

where 0\le t\le2\pi. Then the line integral is

\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=0}^{t=2\pi}\mathbf f(x(t),y(t),z(t))\cdot\dfrac{\mathrm d}{\mathrm dt}\langle x(t),y(t),z(t)\rangle\,\mathrm dt
=\displaystyle\int_0^{2\pi}\langle0,0,3\cos t\rangle\cdot\langle0,-3\sin t,3\cos t\rangle\,\mathrm dt=9\int_0^{2\pi}\cos^2t\,\mathrm dt=9\pi

We can check this result by evaluating the equivalent surface integral. We have

\nabla\times\mathbf f=\langle1,0,0\rangle

and we can parameterize \mathcal M by

\mathbf s(u,v)=\langle3\cos v,3\cos u\sin v,3\sin u\sin v\rangle

so that

\mathrm d\mathbf S=(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv=\langle9\cos v\sin v,9\cos u\sin^2v,9\sin u\sin^2v\rangle\,\mathrm du\,\mathrm dv

where 0\le v\le\dfrac\pi2 and 0\le u\le2\pi. Then,

\displaystyle\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S=\int_{v=0}^{v=\pi/2}\int_{u=0}^{u=2\pi}9\cos v\sin v\,\mathrm du\,\mathrm dv=9\pi

as expected.
7 0
3 years ago
What is f(5) for the function f(x)=2x+7
denis-greek [22]

Answer:

Solution:

f(5)=2×5+7

=10+7

=17

8 0
3 years ago
Read 2 more answers
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