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user100 [1]
3 years ago
11

pllssssssssssssssssssssssssssssssssssssss helppppppppppppp Find all possible values of the digits Y, E, A, R if YYYY - EEE + AA

- R = 1234, and different letters represent different digits.
Mathematics
2 answers:
Nana76 [90]3 years ago
6 0

Answer:

Y = 2

E = 9

A = 1

R = 0

Step-by-step explanation:

2222 - 999 + 11 - 0 =1234

AleksAgata [21]3 years ago
6 0

Answer:

Y = 2

E = 9

A = 1

R = 0

Step-by-step explanation:

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(25 points) Can someone please solve this I just need to see how its solved to understand
aleksley [76]

x = total amount of students in 8th Grade.

we know only one-thrid of the class went, so (1/3)x or x/3 went.

we also know 5 coaches went too, and that the total amount of that is 41.

\bf \stackrel{\textit{one third of all students}}{\cfrac{1}{3}x}+\stackrel{\textit{coaches}}{5}=\stackrel{\textit{total}}{41}\implies \cfrac{x}{3}+5=41\implies \cfrac{x}{3}=41-5 \\\\\\ \cfrac{x}{3}=36\implies x=3(36)\implies x=108

now, to verify, well, what do you get for (108/3) + 5?

4 0
3 years ago
Expression is equivalent to 486 – 9 + 6 + 33 × 2
mojhsa [17]

Answer:

  549

Step-by-step explanation:

A calculator can give you an equivalent expression.

I might work from the middle outward:

  = 486 -3 +33×2

  = 483 +66

  = (480 +60) + (3 +6)

  = 540 + 9

  = 549

7 0
3 years ago
The rectangle below has an area of 1 8 x 3 18x 3 square meters and a length of 2 x 2 2x 2 meters.
motikmotik

Answer:

\text{The width of rectangle}=9x\text{ meters}

Step-by-step explanation:

We have been given that the rectangle has an area of 18x^3 square meters and a length of 2x^{2}. We are asked to find the width of rectangle.

Since we know that area of a rectangle is width times length of the rectangle, so we can find width of our given rectangle by dividing given area by length of rectangle.

\text{Area of rectangle}=\text{Width of rectangle *Length of the rectangle}

\frac{\text{Area of rectangle}}{\text{Length of rectangle}}=\frac{\text{Width of rectangle *Length of the rectangle}}{\text{Legth of rectangle}}

\text{The width of rectangle}=\frac{\text{Area of rectangle}}{\text{Length of rectangle}}

Upon substituting our given values in above formula we will get,

\text{The width of rectangle}=\frac{18x^3\text{ meter}^2}{2x^2\text{ meters}}

\text{The width of rectangle}=\frac{9x^3\text{ meters}}{x^2}

Using exponent rule for quotient \frac{a^m}{a^n}=a^{m-n} we will get,

\text{The width of rectangle}=9x^{3-2}\text{ meters}

\text{The width of rectangle}=9x^{1}\text{ meters}=9x\text{ meters}

Therefore, width of our given rectangle will be 9x meters.

3 0
3 years ago
ILL GIVE BRAINLIEST ! Need help with algebra. random answers get reported.
Alex_Xolod [135]

Answer:

1.2.4

2. -8

3. -5-3

4.10+12+14

5.-10-3

6. 2+2=4

7.5+3=8

8 0
2 years ago
Read 2 more answers
Which of these points lies on the line described by the equation below? y - 4 = -2(x - 6)
ch4aika [34]
Y - y₁ = m(x - x₁)
 y - 4 = -2(x - 6)
 y - 4 = -2(x) + 2(6)
 y - 4 = -2x + 12
   + 4          +   4
      y = -2x + 16

The answer is D, (6, 4).
3 0
3 years ago
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