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Alexandra [31]
3 years ago
14

Ill give 20 points for who ever can help me with these 2 simple questions! Thank you again!

Mathematics
1 answer:
Stella [2.4K]3 years ago
5 0
11. remember
(ab)^c=(a^c)(b^c)
and
(x^m)^n=x^{mn}
so
\pi (6x^9y^5)^2= \pi (6^2)((x^9)^2)((y^5)^2)=\pi(36)(x^{18})(y^{10})
B is right

12. (x^m)(x^n)=x^{m+n}

so
(x^1)(x^2y)(y^2)=(x^1)(x^2)(y^1)(y^2)=x^3y^3
C is answer

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stiks02 [169]
90b + 150g > 500

0.35b + 2.50g < 15.00

what, is the question asking. These might help
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3 years ago
Abram and Fred leave opposite ends of a bike trail 12 miles apart and travel toward each other. Abram is traveling 8 mph faster
Dimas [21]
Abram: 10 mph; Fred: 7 mph
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3 years ago
A supplier of heavy construction equipment has found that new customers are normally obtained through customer requests for a sa
ziro4ka [17]

Answer:

The probability that it will take fewer than six customer contacts to clear the inventory is 0.8%.

Step-by-step explanation:

We have a probability of making an individual sale of p=0.15.

We have 4 units, so the probability of clearing the inventory with n clients can be calculated as:

P=\dbinom{n}{4}p^4q^{n-4}=\dbinom{n}{4}0.15^4\cdot 0.85^{n-4}

As we see in the equation, n has to be equal or big than 4.

In this problem we have to calculate the probability that less than 6 clients are needed to sell the 4 units.

This probability can be calculated adding the probability from n=4 to n=6:

P=\sum_{n=4}^6P(n)=\sum_{n=4}^6 \dbinom{n}{4}0.15^4^\cdot 0.85^{n-4}\\\\\\P=0.15^4(\dfrac{4!}{4!0!}\cdot 0.85^{4-4}+\dfrac{5!}{4!1!}\cdot0.85^{5-4}+\dfrac{6!}{4!2!}0.85^{6-4})\\\\\\P=0.15^4(1\cdot0.85^0+5\cdot0.85^1+15\cdot0.85^2)\\\\\\P=0.00051(1+4.25+10.84)\\\\\\P=0.00051\cdot16.09\\\\\\P=0.008

5 0
3 years ago
Ronald rents a car from Cheap Rent-a-Car for $25 plus $0.05 per mile. Dixon rents a car
wlad13 [49]

Answer:

750 miles

Step-by-step explanation:

Ronald

Rental fee = fixed cost + variable cost

= $25 + $0.05x

Where x = number of miles

Dixon

Rental fee = fixed cost + variable cost

= $40 + $0.03x

How many miles must they both drive for their rental fees to be the same?

Equate the two equations

$25 + $0.05x = $40 + $0.03x

Collect like terms

0.05x - 0.03x = 40 - 25

0.02x = 15

Divide both sides by 0.02

x = 15 / 0.02

= 750 miles

3 0
4 years ago
I need a study buddy plez help me text me at (838) 386-8228
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Answer:

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