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vichka [17]
3 years ago
15

What is the initial value of e=3h+200.

Mathematics
1 answer:
Dmitrij [34]3 years ago
7 0

Answer:h=e-200/3

Step-by-step explanation:

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Please help asappp worth 20
Naily [24]

Answer:

98

Step-by-step explanation:

angles 1 and 2 are congruent, the lines in each side of the shape prove this.

another way to solve if you are not sure is to subtract all of the numbers from 360. all quadrilaterals equal 360 degrees, so if you subtract each of the three angles from 360, you will be left with the last angle.

360-120-44-98=98

5 0
3 years ago
Read 2 more answers
Tom drives 200 miles in 4 hours.
SVETLANKA909090 [29]

His average speed for the rest of the journey was of 48mph.

6 0
3 years ago
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Find the vertices and foci of the hyperbola with equation (x-3)^2/16-(y+4)^2/9 = 1
ladessa [460]

Answer:well first you should start with the problem (x-3)^2/16-(y+4)^2/9=1

Then solve it and you should get the answer

Hope this helps!

Step-by-step explanation:

6 0
3 years ago
the admission fee for a charity event is 7 dollars for children and 10 dollars for adults the event was attended by 700 people a
ollegr [7]
Given:
$7/child
$10/adult
Total people = 700
Total money = $6,400

First, make two equations.
Let a = # of adults & Let c = # of children.
Let p = total people

1.      a+c = 700
2.  10a+7c = 6,400

Then, rearrange the equation to solve for a variable.
c = 700-a

Substitute (700-a) for c, or the # of children in the second equation.
10a+(700-a) = 6400
9a+700 = 6400
9a+700-700 = 6400-700
9a = 5700
9a/9 = 5700/9 
a = 633\frac{1}{3}  = # of adults attended

700-633\frac{1}{3} = c = 66 \frac{2}{3} = # of children attended


4 0
3 years ago
The average telephone bill in a locality is $70, with a standard deviation of $40. In a sample of 50 randomly selected phone con
Sever21 [200]

Using the normal distribution, there is a 0.1894 = 18.94% probability that the sample average will exceed $75.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

The parameters for this problem are given as follows:

\mu = 70, \sigma = 40, n = 50, s = \frac{40}{\sqrt{50}} = 5.66

The probability that the sample average will exceed $75 is <u>one subtracted by the p-value of Z when X = 75,</u> hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = (75 - 70)/5.66

Z = 0.88

Z = 0.88 has a p-value of 0.8106.

1 - 0.8106 = 0.1894.

0.1894 = 18.94% probability that the sample average will exceed $75.

More can be learned about the normal distribution at brainly.com/question/28096232

#SPJ1

3 0
2 years ago
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