1) x'=(3+i√7)/2 & x"=(3-i√7)/2 No real roots.
2) x'=(-2+√14)/2 & x"=(-2-√14)/2
3) x' x" -4
Answer:
1.309
Step-by-step explanation:
Answer:
<u>Use cross-multiplication to solve these</u>
- 1) 6/2 = 4/p ⇒ 6p = 4*2 ⇒ p = 8/6 ⇒ p = 4/3
- 2) 4/k = 8/2 ⇒ 8k = 2*4 ⇒ k = 8/8 ⇒ k = 1
- 3) n/4 = 8/7 ⇒ n = 4*8/7 ⇒ n = 32/7
- 4) 5/3 = x/4 ⇒ x = 4*5/3 ⇒ x = 20/3
Answer:
2nd option
Step-by-step explanation:
To convert from (x, y ) → (r, θ )
where
r =
θ = ( )
Here (x, y ) = (- 4, 5 ), a point in the 2nd quadrant
r = = =
θ = ( ) ≈ 51.3° ← related acute angle , then
θ = 180° - 51.3° = 128.7°
Thus
(- 4, 5 ) → (, 128.7° ) in polar form