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Thepotemich [5.8K]

3 years ago

10

Ahmed, Walid and Faisal made $1446 profit from selling used books. If Ahmed to receive double amount of Faisal and Walid to rece

ive triple amount of Faisal. How much does each one receive? any help pls urgent

1 answer:

Strike441 [17]3 years ago

7 0

I would say take that a divided

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15 points please help me ASAP

gayaneshka [121]

The distance between the means is equal to 4.
The mean absolute deviation (MAD) for player A is equal to 2.
The mean absolute deviation (MAD) for player B is equal to 2.
Distance between the means = two (2) times the MAD.
There is some overlap and the distance between the means is between 1 times the MAD and 5 times the MAD.

<h3>What is a number line?</h3>

A number line can be defined as a type of graph with a graduated straight line which contains both positive and negative numerical values that are placed at equal intervals along its length.

<h3>What is a line plot?</h3>

A line plot can be defined as a type of graph that is used to graphically represent a data set above a number line, while using crosses, dots, or any other mathematical symbol.

<h3>What is a mean?</h3>

A mean is also referred to as an average and it can be defined as a ratio of the sum of the total number in a data set (population) to the frequency of the data set.

Mathematically, the distance between the means of both players A and B is given by:

Distance = Mean of player B - Mean of player A

Distance = 10 - 6

Distance = 4.

The mean absolute deviation (MAD) for player A is given by:

MAD A = 1/11[2(3 - 6) + 2(4 - 6) + (5 - 6) + (6 - 6) + (7 - 6) + 2(8 - 6) + 2(9 - 6)]

MAD A = 1/11[2(3) + 2(2) + (1) + (0) + (1) + 2(2) + 2(3)]

MAD A = 1/11[6 + 4 + 1 + 0 + 1 + 4 + 6]

MAD A = 1/11 × [22]

MAD A = 22/11

MAD A = 2.

Also, the mean absolute deviation (MAD) for player B is given by:

MAD B = 1/11[2(7 - 10) + 2(8 - 10) + (9 - 10) + (10 - 10) + (11 - 10) + 2(12 - 10) + 2(13 - 10)]

MAD B = 1/11[2(3) + 2(2) + (1) + (0) + (1) + 2(2) + 2(3)]

MAD B = 1/11[6 + 4 + 1 + 0 + 1 + 4 + 6]

MAD B = 1/11 × [22]

MAD B = 22/11

MAD B = 2.

Therefore, distance between the means = two (2) times the MAD.

Distance = Means × MAD

4 = 2 × 2.

In conclusion, we can infer and logically deduce that there is some overlap and the distance between the means of both players A and B is between one (1) times the MAD and five (5) times the MAD.

Read more on line plot here: brainly.com/question/8989301

#SPJ1

6 0

1 year ago

Write an equation of the line in slope-intercept form (0,-2) ,(2,2)

Kipish [7]

Answer:

y=2x-2

Step-by-step explanation:

Slope intercept Formula: y=mx+b

y= Y coordinate

m = slope

x = x coordinate

b = y intercept

Point Slope Formula: y-y1=m(x-x1)

Slope Formula: m= y2-y1 / x2-x1

2 - (-2) / 2-0 = 4 / 2 = 2

y- (-2) = 2 (x - 0) = y+2=2x-0

y=2x-2

3 0

3 years ago

Among persons donating blood to a clinic, 85% have Rh+ blood (that is, the Rhesus factor is present in their blood.) Six people

Leona [35]

Answer:

a) There is a 62.29% probability that at least one of the five does not have the Rh factor.

b) There is a 22.36% probability that at most four of the six have Rh+ blood.

c) There need to be at least 8 people to have the probability of obtaining blood from at least six Rh+ donors over 0.95.

Step-by-step explanation:

For each person donating blood, there are only two possible outcomes. Either they have Rh+ blood, or they do not. This means that we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$p = 0.85, n = 6$ .

a) fine the probability that at least one of the five does not have the Rh factor.

Either all six have the factor, or at least one of them do not. The sum of the probabilities of these events is decimal 1. So:

$P(X < 6) + P(X = 6) = 1$

$P(X < 6) = 1 - P(X = 6)$

In which:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{6,6}.(0.85)^{6}.(0.15)^{0} = 0.3771$

So

$P(X < 6) = 1 - P(X = 6) = 1 - 0.3771 = 0.6229$

There is a 62.29% probability that at least one of the five does not have the Rh factor.

b) find the probability that at most four of the six have Rh+ blood.

Either more than four have Rh+ blood, or at most four have. So

$P(X \leq 4) + P(X > 4) = 1$

$P(X \leq 4) = 1 - P(X > 4)$

In which

$P(X > 4) = P(X = 5) + P(X = 6)$

$P(X = 5) = C_{6,5}.(0.85)^{5}.(0.15)^{1} = 0.3993$

$P(X = 6) = C_{6,6}.(0.85)^{6}.(0.15)^{0} = 0.3771$

$P(X > 4) = P(X = 5) + P(X = 6) = 0.3993 + 0.3771 = 0.7764$

$P(X \leq 4) = 1 - P(X > 4) = 1 - 0.7764 = 0.2236$

There is a 22.36% probability that at most four of the six have Rh+ blood.

c) The clinic needs six Rh+ donors on a certain day. How many people must donate blood to have the probability of obtaining blood from at least six Rh+ donors over 0.95?

With 6 donors:

$P(X = 6) = C_{6,6}.(0.85)^{6}.(0.15)^{0} = 0.3771$

37.71% probability of obtaining blood from at least six Rh+ donors over 0.95.

With 7 donors:

$P(X = 6) = C_{7,6}.(0.85)^{6}.(0.15)^{1} = 0.3960$

0.3771 + 0.3960 = 0.7764 = 77.64% probability of obtaining blood from at least six Rh+ donors over 0.95.

With 8 donors

$P(X = 6) = C_{8,6}.(0.85)^{6}.(0.15)^{2} = 0.2376$

0.3771 + 0.3960 + 0.2376 = 1.01 = 101% probability of obtaining blood from at least six Rh+ donors over 0.95.

There need to be at least 8 people to have the probability of obtaining blood from at least six Rh+ donors over 0.95.

5 0

3 years ago

13 points plus brainliest to the correct answer!

TEA [102]

The equation of a straight line is given by:

y = mx + c

where m is the slope and c is the y-intercept.

From the given graph, the y-intercept is 1.

The slope of a straight line is given by:

$m= \frac{y_2-y_1}{x_2-x_1}$

Where $(x_1,y_1)$ and $(x_2,y_2)$ are two points on the line.

From the graph, (0, 1) and (14, 8) are two points on the line, thus:

$m= \frac{8-1}{14-0} = \frac{7}{14} = \frac{1}{2}$

Therefore, the equation representing the graph is $y= \frac{1}{2} x+1$

8 0

3 years ago

Read 2 more answers

True or false ? The polynomial below is a perfect square trinomial of the form A2-2AB+B2 4x2-16x+16

Vlad1618 [11]

True

4x^2 -16x +16 = (2x -4)^2

A = 2x
B = 4

3 0

3 years ago