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Thepotemich [5.8K]
3 years ago
10

Ahmed, Walid and Faisal made $1446 profit from selling used books. If Ahmed to receive double amount of Faisal and Walid to rece

ive triple amount of Faisal. How much does each one receive? any help pls urgent
Mathematics
1 answer:
Strike441 [17]3 years ago
7 0
I would say take that a divided
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Find the circumference of the pizza to the nearest hundredth.
Andrew [12]
56.52 inches because 18 is the diameter and 18 times 3.14 is 56.52
5 0
3 years ago
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Simplify the expression. Write your answer as a power.<br><br> (−5/7)^8⋅(−5/7)^9
dem82 [27]

Answer: (-\frac{5}{7})^{17}

Step-by-step explanation:

The expression can be simplified by applying the a properties of exponents, specifically the Product of powers, which states that:

(b^a)(b^c)=b^{(a+c)

Where b is the base and a and c are exponents.

 Then simplify it by rewriting the base (-\frac{5}{7}) and adding the exponents of the expression (8 and 9).

You will get the expression simplified and written as a power:

(-\frac{5}{7})^8(-\frac{5}{7})^9=(-\frac{5}{7})^{(8+9)}=(-\frac{5}{7})^{17}

3 0
3 years ago
6m + 15n- 12p/n for m = -3.5, n=4, and p=3
Alexus [3.1K]

Answer: B. 30

Step-by-step explanation:

First, you re-write the expression

6(-3.5) + 15(4) - 12(3/4)

Then multiply all the parts correctly.

-21 + 60 - 9

-21 + 60 = 39

-9

= 30

8 0
3 years ago
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What is the domain and range of the graph below in interval notation? If union is needed, use Capital U. If infinity is needed u
elena55 [62]

Answer:

DOMAIN: (-\infty,1]\cup(2,\infty)

RANGE: (-\infty,\infty)

Step-by-step explanation:

The domain of a graph is the span of x-values covered by the graph, while the range of a graph is the span of y-values covered by the graph.

DOMAIN:

From the graph, we can see that the x-values covers everything to the left of x=1. Then we stop and then continue beginning at x=2 all the way until positive infinity.

However, note that at x=1, the dot is a closed circle while at x=2, the dot is an open circle. Thus, we will include x=1 into our domain but not include x=2 into our domain.

So, our domain is all values greater than or less than 1, and all values greater than 2.

In interval notation, this is:

(-\infty,1]\cup(2,\infty)

We use brackets with the 1 because we include it in our domain and we use parentheses with the 2 since we do not.

RANGE:

Looking at the graph, it seems that all y-values are covered. The part of the graph on the left covers all y-values less than or equal to 3, while the part of the graph on the right covers all y-values greater than -1. Thus, all y-values are covered.

Our range is all real numbers.

In interval notation, this is:

(-\infty,\infty)

5 0
3 years ago
Solve the given system of equations using either Gaussian or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTI
cricket20 [7]

Answer:

The system has infinitely many solutions

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

There are three elementary matrix row operations:

  1. Switch any two rows
  2. Multiply a row by a nonzero constant
  3. Add one row to another

To solve the following system

\begin{array}{ccccc}x_1&-3x_2&-2x_3&=&0\\-x_1&2x_2&x_3&=&0\\2x_1&+3x_2&+5x_3&=&0\end{array}

Step 1: Transform the augmented matrix to the reduced row echelon form

\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]

This matrix can be transformed by a sequence of elementary row operations

Row Operation 1: add 1 times the 1st row to the 2nd row

Row Operation 2: add -2 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1

Row Operation 4: add -9 times the 2nd row to the 3rd row

Row Operation 5: add 3 times the 2nd row to the 1st row

to the matrix

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

which corresponds to the system

\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}

The system has infinitely many solutions.

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

7 0
3 years ago
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