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elena-s [515]
3 years ago
15

Any one that knows this please help thanks!

Mathematics
1 answer:
OLga [1]3 years ago
5 0

Replace each occurrence of x by 7. So we have:-

7^2 + 3 / 7 - 9

= 52 / -2

= -26 answer

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A paper container in the shape of a right circular cone has a radius of 3 inches and a height of 8 inches. Determine and state t
Scrat [10]

Given:

Radius of the cone = 3 inches

Height of the cone = 8 inches

To find:

The volume of the cone, in terms of  π.​

Solution:

We know that, the volume of a cone is:

V=\dfrac{1}{3}\pi r^2h

Putting r=3,h=8, we get

V=\dfrac{1}{3}\pi (3)^2(8)

V=\dfrac{1}{3}\pi (9)(8)

V=\dfrac{72}{3}\pi

V=24\pi

Therefore, the volume of the cone is 24\pi.

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2 years ago
Mike has a net spendable income of $1,400. He decides to set up a budget before looking for an apartment or a car. He sets up hi
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C.) Mike is using the minimum recommended percentages for food, housing, and transportation. The costs are likely to exceed the expenses in each category.


7 0
3 years ago
Read 2 more answers
Which statement best explains whether the table represents a linear or nonlinear function?
dalvyx [7]

Answer:

C

Step-by-step explanation:

7 0
3 years ago
Given f(x) =
sergejj [24]

Answer:

A

Step-by-step explanation:

We are given the function:

\displaystyle f(x) = \left\{        \begin{array}{ll}            2\cos(\pi x) \text{ for }  x \leq -1 \\ \\          \displaystyle   \frac{2}{\cos(\pi x)}\text{ for } x > -1        \end{array}    \right.

And we want to find:

\displaystyle \lim_{x\to -1}f(x)

So, we need to determine whether or not the limit exists. In other words, we will find the two one-sided limits.

Left-Hand Limit:

\displaystyle \lim_{x\to-1^-}f(x)

Since we are approaching from the left, we will use the first equation:

\displaystyle =\lim_{x\to -1^-}2\cos(\pi x)

By direct substitution:

=2\cos(\pi (-1))=2\cos(-\pi)=2(-1)=-2

Right-Hand Limit:

\displaystyle \lim_{x\to -1^+}f(x)

Since we are approaching from the right, we will use the second equation:

=\displaystyle \lim_{x\to -1^+}\frac{2}{\cos(\pi x)}

Direct substitution:

\displaystyle =\frac{2}{\cos(\pi (-1))}=\frac{2}{\cos(-\pi)}=\frac{2}{(-1)}=-2

So, we can see that:

\displaystyle \displaystyle \lim_{x\to-1^-}f(x)=\displaystyle \lim_{x\to -1^+}f(x) =-2

Since both the left- and right-hand limits exist and equal the same thing, we can conclude that:

\displaystyle \lim_{x \to -1}f(x)=-2

Our answer is A.

8 0
3 years ago
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