Answer:
500 pounds
Step-by-step explanation:
Let the pressure applied to the leverage bar be represented by p
Let the distance from the object be represented by d.
The pressure applied to a leverage bar varies inversely as the distance from the object.
Written mathematically, we have:

Introducing the constant of proportionality

If 150 pounds is required for a distance of 10 inches from the object

Therefore, the relationship between p and d is:

When d=3 Inches

The pressure applied when the distance is 3 inches is 500 pounds.
No cap absolutely I think its the 2nd one tho
The correct value for m is 0(zero). :)