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Pepsi [2]
3 years ago
8

Solve the inequality for w. - 11 >w- 19

Mathematics
2 answers:
Thepotemich [5.8K]3 years ago
8 0

Answer:

<h2>w < 8</h2>

Step-by-step explanation:

-11>w-19\qquad\text{add 19 to both sides}\\\\-11+19>w-19+19\\\\8>w\to w

Vaselesa [24]3 years ago
5 0

Answer:

w < 8

Step-by-step explanation:

This means w can be any number below 8.

Example;

w = 7

w = 6

w = 5

and so on...

<em>(</em><em>Changed</em><em> </em><em>original</em><em> </em><em>answer</em><em>.</em><em> </em><em>Thought</em><em> </em><em>it</em><em> </em><em>had</em><em> </em><em>said</em><em> </em><em>-11</em><em> </em><em><</em><em> </em><em>w</em><em> </em><em>-</em><em> </em><em>1</em><em>9</em><em>)</em>

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Answer:

The answer is 8 units! Hope this helps!

Step-by-step explanation:f the length of any one side of the square is x, then the area is x2, and the perimeter is 4x. If the area is twice the perimeter, x2 = 2(4x), and x2 − 8x= 0. By factoring, we see this equation is equivalent to x(x − 8) = 0, which has solutions 0 and 8. The length cannot be 0, so it must be 8 units.

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6 0
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Read 2 more answers
A person invests 7000 dollars in a bank. The bank pays 5.5% interest compounded
kotykmax [81]

The time required to get a total amount of $13,200.00 with compounded interest on a principal of $7,000.00 at an interest rate of 5.5% per year and compounded 12 times per year is 11.559 years. (about 11 years 7 months)

Answer:

t = 11.559 years

<h3>Compound Interest </h3>

Given Data

  • Principal P= $7000
  • Rate r= 5.5%
  • Final Amount A = $13200
  • Time t = ??

(about 11 years 7 months)

Calculation Steps:

First, convert R as a percent to r as a decimal

r = R/100

r = 5.5/100

r = 0.055 per year,

Then, solve the equation for t

t = ln(A/P) / n[ln(1 + r/n)]

t = ln(13,200.00/7,000.00) / ( 12 × [ln(1 + 0.055/12)] )

t = ln(13,200.00/7,000.00) / ( 12 × [ln(1 + 0.0045833333333333)] )

t = 11.559 years

Learn more about compound interest here:

brainly.com/question/24924853

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2 years ago
Find the variable 6x-8=34
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x is the variable

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