A=(a+b/2)h is the formula hope that helps
Answer:
Step-by-step explanation:
Find the measure of the vertex angle ∠ABD of an isosceles triangle
we know that
An isosceles triangle has two equal sides and two equal angles
In this problem
∠ABD=∠BAD= ----> the angles of the base are equals
Find the measure of the vertex angle
∠ABD= ------> the sum of the internal angles of a triangle is equal to
Step 2
Find the measure of the angle ∠CBD in the equilateral triangle
we know that
A equilateral triangle has three equal sides and three equal angles
The measure of the internal angle in a equilateral triangle is
so
∠CBD=
Step 3
Find the measure of the angle ∠ABC
∠ABC=∠ABD+∠DBC
substitute the values
∠ABC=
therefore
the answer is
the measure of the angle ∠ABC is
9x^2+t+25=(ax+b)^2
9x^2+t+25=a^2*x^2+2abx+b^2 so
a^2=9 so a=3
b^2=25 so b=5 then
t=2ab using a and b from above
t=2*3*5=30
So the missing term is 30x
The answer is the test contains 10 3pt questions and 14 5 pt questions. Any questions please just ask!!! thank you!
