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kupik [55]
4 years ago
10

Write a program that prompt the user to enter the coordinate of two points (x1, y1) and (x2,y2), and displays the slope of the l

ine that connects the two points.
Computers and Technology
1 answer:
zzz [600]4 years ago
3 0

Answer:

Here is code in C++.

//include headers

#include <bits/stdc++.h>

using namespace std;

//main function

int main() {

//variables to store coordinates

float x1,x2,y1,y2;

cout<<"Please Enter the coordinate of first point (x1,y1): ";

// reading coordinate of first point

cin>>x1>>y1;

cout<<"Please Enter the coordinate of second point (x2,y2): ";

// reading coordinate of second point

cin>>x2>>y2;

//calculating Slope of the line that connects these points

float m=(x2-x1)/(y2-y1);

cout<<"Slope of the line that connects these two points is :  "<<m<<endl;

}

Explanation:

Declare four variables x1,x2,y1,y2 to store the coordinate of both points.

Read the coordinate of both the point from user. Calculate the slop of the

line which connects these two points with the formula m=(x2-x1)/(y2-y1).

Output:

Please Enter the coordinate of first point (x1,y1): 1 3                                                                                                        

Please Enter the coordinate of second point (x2,y2): 5 12                                                                                                      

Slope of the line that connects these two points is :  0.444444  

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Answer:

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Part (b) n(A∪B∪C) = 54

Explanation:

n(A) = no. of students who took Math 2A

n(B) = no. of students who took Math 2B

n(C) = no. of students who took Math 2C

n(A∩B) = no. of students who took both Math 2A and 2B

n(A∩C) = no. of students who took both Math 2A and 2C

n(B∩C) = no. of students who took both Math 2B and 2C

n(A∩B∩C) = no. of students who took all three Math 2A, 2B and 2C

n(A∪B∪C) = no. of total students in a group

∩ represents Intersection and ∪ represents Union

Part (a)

n(A∪B∪C) = n(A) + n(B) + n(C) - n(A∩B) - n(A∩C) - n(B∩C) + n(A∩B∩C)  

Where n(A∩B∩C) represents the number of students who took all three classes and n(A∪B∪C) represents the total number of students in group A

157 = 51 + 80 + 70 - 15 - 20 - 13 + n(A∩B∩C)

Re-arranging the equation to solve for n(A∩B∩C) since we want to find out those students who took all three classes

n(A∩B∩C) = 157 - 51 - 80 - 70 + 15 + 20 + 13

n(A∩B∩C) = 4

So there are 4 students in group A who took all three classes

Part (b)

n(A∪B∪C) = n(A) + n(B) + n(C) - n(A∩B) - n(A∩C) - n(B∩C) + n(A∩B∩C)

This time we are given n(A∩B∩C) students who took all three classes and want to find n(A∪B∪C) that is total number of students

n(A∪B∪C) = 28 + 28 + 25 - 11 - 9 - 10 + 3

n(A∪B∪C) = 54

So there are total 54 students in group B

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3 years ago
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Answer:

please find the attachment of the flowchart.

Explanation:

In this question, a start block is used to start the program, in the parallelogram box we input the value from the user end and in the diamond box, we check the input is not equal to 0. In the next diamond box, it checks the given input value and print value, and at the last, we stop the code.

Please find the program and its output in the attached file.

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Answer:

Here are the for loop for the given question.

 for (i = 0; i < NUM_VALS; i++)  // for loop

       {

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       if(i==(NUM_VALS-1))  // if block

       System.out.print(hourlyTemp[i]);

  /* if i is not equal then just print the value with comma.*/

       else   // else block

       System.out.print(hourlyTemp[i] + ", ");

       }

Explanation:

In this we iterating the for loop  and check the condition

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If i is not equal then just print the value with comma .

Output:

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zhannawk [14.2K]

Answer:

see explaination for code

Explanation:

Implement using JAVA

import java.util.Scanner;

public class Multiples {

public static boolean isMultiple(int first, int second){

if(second%first == 0)

return true;

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}

public static void main(String[] args) {

Scanner sc = new Scanner(System.in);

while(true){

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int first = sc.nextInt();

System.out.print("Enter a second number: ");

int second = sc.nextInt();

if(isMultiple(first, second))

System.out.println(second+" is multiple of "+first);

else

System.out.println(second+" is not multiple of "+first);

System.out.print("Do you want to enter another pair(y/n)? ");

char c = sc.next().charAt(0);

if('y' != Character.toLowerCase(c))

break;

}

}

}

/*

Sample run:

Enter one number: 7

Enter a second number: 28

28 is multiple of 7

Do you want to enter another pair(y/n)? y

Enter one number: 8

Enter a second number: 24

24 is multiple of 8

Do you want to enter another pair(y/n)? y

Enter one number: 4

Enter a second number: 2

2 is not multiple of 4

Do you want to enter another pair(y/n)? n

*/

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