The question requires that we have to state the hypothesis:
null hypothesis;H0: u1 < u2, the alternate hypothesis;H1: u1 > u2. The one tail test is what is to be used.
<h3>A.
How to state the hypothesis</h3>
H0: u1 < u2
H1: u1 > u2
The one tail test statistic is what is to be used here
<h3>B.
standard error </h3>

= 1.49
The df = 17 + 15 - 2
= 30
test statistic = 18.9 - 17.4 / 1.49
= 1.007
We have the critical value on excel as T.INV(0.9,30)
= 1.310
E. At 0.1, we can conclude that t-value (1.007) does not lies in the rejection area. We fail to reject the null hypothesis. Hence we conclude that the mean vacation with the unlimited plan is greater.
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Part A.
*To find the sales tax (6%) amount: $18.50 x .06 = $1.11 is the sales tax on a dozen carnations
Part B.
*To find the total cost of a dozen carnations plus the sales tax: $18.50 + $1.11 = $19.61 this is the total cost
X = x
to solve, subtract both sides by x:
0 = 0
x is always equals to x so infinite solutions
We substitute in c using 9, it will be as follows:
5 ×[(-6×9)+4] = 5 × (-54+4) = 5 × (-50) = -250