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WINSTONCH [101]
3 years ago
13

Clark has 20 trading cards and he buys (p) trading cards from the store. He gave his friend Jenny (k) trading cards as a gift fo

r her birthday. How many trading cards does Clark have left.
Mathematics
1 answer:
NikAS [45]3 years ago
5 0
(20 + p) - k = how many cards he has left
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Find the slope of the line graphed below.
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8/5

Step-by-step explanation:

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If you wanted a 40 foot tree in your yard, how much faster would a poplar, which grows 8 feet per year, reach that goal than a r
Verizon [17]

Answer:

Not totally sure if i'm reading the question right buuuut;

the answer is (I think) a poplar would reach 40 feet high in 5 years, while the red maple would reach the goal in 8.

Step-by-step explanation:

using division, 40/8 = 5 years

40/ 5 = 8 years.

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5 0
4 years ago
Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c
GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(c) The value of P (X < 30) is 0.9502.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0

The value of E (X) is 10.

The parameter λ is:

\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10

(a)

Compute the value of P (X > 10) as follows:

P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353

Thus, the value of P (X > 20) is 0.1353.

(c)

Compute the value of P (X < 30) as follows:

P(X

Thus, the value of P (X < 30) is 0.9502.

(d)

It is given that, P (X < x) = 0.95.

Compute the value of <em>x</em> as follows:

P(X

Take natural log on both sides.

ln(e^{-0.10x})=ln(0.05)\\-0.10x=-2.996\\x=\frac{2.996}{0.10}\\ =29.96\\\approx30

Thus, the value of x is 30.

7 0
3 years ago
Given f(x)=x^2-2x find f(6)
-BARSIC- [3]

Step-by-step explanation:

In the picture, I hope that it's a clear solution.

7 0
3 years ago
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