A ladder is placed against a wall such that the top is 8 feet above the ground. If the ladder is 10 feet long, how far away from
1 answer:
Answer:
6 feet
Step-by-step explanation:
Consider the right triangle formed by the wall, ladder and ground.
Let the distance the ladder is from the wall be d , then
Using Pythagoras' identity in the right triangle
The square on the hypotenuse ( ladder) is equal to the sum of the squares on the other 2 sides ( wall and d ), then
d² + 8² = 10²
d² + 64 = 100 ( subtract 64 from both sides )
d² = 36 ( take the square root of both sides )
d = = 6
That is the ladder is 6 feet away from the wall
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Answer:
Step-by-step explanation:
Angle sum property of triangle: Sum of all the angles of a triangle is 180
Alternate interior angles: When two parallel lines are intersected by a transversal, the pair of angles on the inner side of each of these lines but on the opposite side of the transversal are called alternate interior angles
In ΔABC,
∠1 + 90 + 38 = 180 {angle sum property of triangle}
∠1 + 128 = 180
∠1 = 180 - 128
AB // CD and AC is transversal.
{Alternate interior angles are equal}
In ΔACD,
∠2 + ∠3 + 63 = 180 {angle sum property of triangle}
∠2 + 38 +63 = 180
∠2 + 101 =180
∠2 = 180 - 101
