Ask question

Ask question

All categories

2 years ago

5

There are 25 pupils in a class. The table shows information about their test results in maths and English. How many pupils had a

higher level in maths than in English?

1 answer:

Nadusha1986 [10]2 years ago

4 0

Answer:

12

Step-by-step explanation:

2+2+1+1+6=12

$2 + 2 + 1 + 1 + 6 = 12$

You might be interested in

What is the value of one divided by zero?

Soloha48 [4]

Answer:

5

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

PLZZZZZZ NEED HELP!!!!!!!

fredd [130]

Answer:

angle B=120º

Step-by-step explanation:

15+45=60

We know that all triangles have angle measures that equal 180

So 180-60=120

angle B=120º

7 0

3 years ago

What makes headlines? (Geojoke answer) (this is for trigonometric ratios)

Fudgin [204]

Answer:

sorry what do you mean

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

What is n-9 divided by 10=-2

DerKrebs [107]

The value of n is 11.

<u>Step-by-step explanation</u>:

The given expression is (n-9) ÷ 10 = -2

<u>To find the value of n</u> :

From the expression, it is determined that (n-9) is the numerator and 10 is the denominator.
Cross multiply the denominator in the left side of the expression to the another side.

The expression becomes (n-9) = (10 $\times$ -2).

⇒ n-9 = -20

Keep the n term on one side and the constants on other side.

⇒ n = -20+9

⇒ n = -11

Therefore, the value of n is 11.

3 0

3 years ago

Solve the matrix equation for a, b, c, and d. [1 2] [a b] [6 5][3 4] [c d]= [19 8]

Anit [1.1K]

Answer:

The answer is " $\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}$ ".

Step-by-step explanation:

$\bold{\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]}$

Solve the L.H.S part:

$\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\\\\\\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]$

After calculating the L.H.S part compare the value with R.H.S:

$\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]= \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]} \\\\$

$\to a+2c =6....(i)\\\\\to b+2d =5....(ii)\\\\\to 3a+4c =19....(iii)\\\\\to 3b+4d = 8 ....(iv)\\\\$

In equation (i) multiply by 3 and subtract by equation (iii):

$\to 3a+6c=18\\\to 3a+4c=19\\\\\text{subtract}... \\\\\to 2c = -1\\\\\to c= - \frac{1}{2}$

put the value of c in equation (i):

$\to a+ 2 (- \frac{1}{2})=6\\\\\to a- 2 \times \frac{1}{2}=6\\\\\to a- 1=6\\\\\to a =6 +1\\\\\to a = 7\\$

In equation (ii) multiply by 3 then subtract by equation (iv):

$\to 3b+6d=15\\\to 3b+4d=8\\\\\text{subtract...}\\\\\to 2d = 7\\\\\to d= \frac{7}{2}\\$

put the value of d in equation (iv):

$\to 3b+4 (\frac{7}{2})=8\\\\\to 3b+4 \times \frac{7}{2}=8\\\\\to 3b+14=8\\\\\to 3b =8-14\\\\\to 3b = -6\\\\\to b= \frac{-6}{3}\\\\\to b= -2$

The final answer is " $\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}$ ".

4 0

3 years ago