5 x5 x 5 divided by 3 times 290
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Answer:
After solve the equations we get value of k=3
Step-by-step explanation:
We need to find value of k for which the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent.
If the lines are concurrent, they pass through same point.
Let:
First solving equation 1 and 2 to find values of x and y
From eq(1) we find value of x and put it in eq(2)
After solving we get value of y=-1
Now putting in eq(1) to get value of x
So, Value of x= 2
Now put value of x=2 and y=-1 into eq(3) to find value of k
So, After solve the equations we get value of k=3