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brilliants [131]
3 years ago
13

Jillian walked 0.5 miles before she started jogging at an average pace of 5 miles per hour. The equation d = 0.5 + 5t can be use

d to relate the total distance, d, in miles to the time, t, that Jillian spent jogging. What are the independent and dependent variables?
The independent variable is distance and the dependent variable is time.
The independent variable is time and the dependent variable is distance.
The independent variable is distance and the dependent variable is speed.
The independent variable is speed and the dependent variable is distance.
Mathematics
1 answer:
castortr0y [4]3 years ago
4 0

Answer:

The answer is option 2.

Step-by-step explanation:

In the question, the independent variable is time and dependent is distance. As the time changes, the distance will also change it means the distance depends on time.

For example,

d = 0.5 + 5t

Let t = 1,

d = 0.5 + 5(1)

d = 5.5 \: miles

Let t = 5,

d = 0.5 + 5(5)

d = 25.5 \: miles

Therfore, as time increases, distance will also increase.

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Tina is making a scale model of A monument that is 155 feet tall she uses a scale of 1 inch = 5 feet how tall should Tina make h
fenix001 [56]

Tina should make 31 inch tall model to replicate 155 feet tall monument.

Step-by-step explanation:

This problem can be solved by direct unitary methods easily-

Firstly, Scale is the ratio of the dimension of the original substance to the dimension of a model

Scale= original dimension/ model dimension

Model is the miniaturised representation of a substance.

The monument is 155 feet tall

Tina replicates it with a scale 1inch: 5 feet

Thus, this means that Tina would need 155*1/5 = 31 inch tall model to replicate the complete length of the monument.

Hence Tina needs to make 31-inch tall model.

3 0
2 years ago
Read 2 more answers
If G(x) = 3x + 1, then G -1(1) is<br> 4<br> 1/3<br> 0
Eduardwww [97]

Answer:

0


Step-by-step explanation:

g(x) = 3x + 1 \\\ y = 3x + 1


Changing x to y and y to x:


x = 3y + 1 \\\ 3y = x - 1 \\\ y = \frac{x - 1}{3} \\\ g^{-1}(x) = \frac{x - 1}{3} \\\ g^{- 1} (1) = \frac{1 - 1}{3} \\\ g^{- 1} (1) = 0


I hope I helped you.

4 0
3 years ago
Factor completely x^3 + 1/8
maksim [4K]

Answer:

((2 x + 1) (4 x^2 - 2 x + 1))/8

Step-by-step explanation:

Factor the following:

x^3 + 1/8

Put each term in x^3 + 1/8 over the common denominator 8: x^3 + 1/8 = (8 x^3)/8 + 1/8:

(8 x^3)/8 + 1/8

(8 x^3)/8 + 1/8 = (8 x^3 + 1)/8:

(8 x^3 + 1)/8

8 x^3 + 1 = (2 x)^3 + 1^3:

((2 x)^3 + 1^3)/8

Factor the sum of two cubes. (2 x)^3 + 1^3 = (2 x + 1) ((2 x)^2 - 2 x + 1^2):

((2 x + 1) ((2 x)^2 - 2 x + 1^2))/8

1^2 = 1:

((2 x + 1) ((2 x)^2 - 2 x + 1))/8

Multiply each exponent in 2 x by 2:

((2 x + 1) (2^2 x^2 - 2 x + 1))/8

2^2 = 4:

Answer:  ((2 x + 1) (4 x^2 - 2 x + 1))/8

5 0
3 years ago
Read 2 more answers
Joe's hot dog stand is only open for lunch. of today's sales 26% came from selling plain hot dogs. Since the hot dog stand made
meriva
97 then add and find your multiplying

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X + 2x - 4x + 9 combine terms
Scilla [17]

Answer: -x+9

Step-by-step explanation:

5 0
3 years ago
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