Shifting a circle results to changes in the coordinates of the circle. For instance, if the coordinates of the center of the circle is taken to be (0,0), the new coordinates will be [(0+5),(0+2)] after shifting. The equation of the circle will also change with the same margin.
That is, the new equation will be;
(5+x)^2+(2+y)^2 =19
Notice, only the coordinates changes.
The answer to this is,1/4.
The question in Englih is
<span>From a cardboard sheet 35 cm long and 20 cm wide, Masha cut out four squares of 1 dm2 each. Find the area of the cardboard residue. Answer the question in dm2
</span>
Step 1
<span>convert cm to dm
</span>we know that
1 cm is---------------> 0.10 dm
then
35 cm--------------> 3.5 dm
20 cm--------------> 2 dm
Step 2
find the area of the cardboard
Area=3.5*2=7 dm²
Step 3
find the area of the cardboard residue
Area=7-4*1=3 dm²
the answer is 3 dm²
<span>the answer in Russian
</span>
Шаг 1
преобразовать cm в дм
мы знаем это
1 cm ---------------> 0.10 дм
тогда
35 cm--------------> 3.5 дм
20 cm--------------> 2 дм
Шаг 2
найти область картона
Площадь=3.5*2=7 дм²
Шаг 3
<span>найти область остатка картона
</span>Площадь=7-4*1=3 дм²
ответ 3 дм²
ответ 3 дм²
Best Answer: 2 LiCl = 2 Li + Cl2
mass Li = 56.8 mL x 0.534 g/mL=30.3 g
moles Li = 30.3 g / 6.941 g/mol=4.37
the ratio between Li and LiCl is 2 : 2 ( or 1 : 1)
moles LiCl required = 4.37
mass LiCl = 4.37 mol x 42.394 g/mol=185.3 g
Cu + 2 AgNO3 = Cu/NO3)2 + 2 Ag
the ratio between Cu and AgNO3 is 1 : 2
moles AgNO3 required = 4.2 x 2 = 8.4 : but we have only 6.3 moles of AgNO3 so AgNO3 is the limiting reactant
moles Cu reacted = 6.3 / 2 = 3.15
moles Cu in excess = 4.2 - 3.15 =1.05
N2 + 3 H2 = 2 NH3
moles N2 = 42.5 g / 28.0134 g/mol=1.52
the ratio between N2 and H2 is 1 : 3
moles H2 required = 1.52 x 3 =4.56
actual moles H2 = 10.1 g / 2.016 g/mol= 5.00 so H2 is in excess and N2 is the limiting reactant
moles NH3 = 1.52 x 2 = 3.04
mass NH3 = 3.04 x 17.0337 g/mol=51.8 g
moles H2 in excess = 5.00 - 4.56 =0.44
mass H2 in excess = 0.44 mol x 2.016 g/mol=0.887 g
Answer:
Always
Step-by-step explanation:
