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motikmotik
3 years ago
14

Which quadrant contains the vertex of the following: f(x) =–2x² –8x+11

Mathematics
1 answer:
leonid [27]3 years ago
4 0
Quadrant 2 contains the vertex of f(x)=-2x^2-8x+11
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TOY has coordinates T (-3, 4), O (-4, 1) and Y (-2, 3). a translation maps point T to T' (-1, 1). find the coordinates of O' and
NeX [460]

Answer:

Answer:  The correct option is (A) O' (−2, −2); Y' (0, 0).

Step-by-step explanation:  Given that the co-ordinates of the vertices of ΔTOY are T(−3, 4), O (−4, 1), and Y (−2, 3). A translation maps point T to T' (−1, 1).

We are to find the co-ordinates of the points O' and Y'.

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T(−3, 4)   ⇒   T' (−1, 1).

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and

That is, the transformation rule is

(a, b) ⇒ (a+2, b-3).

Therefore,

co-ordinates of O' are (-4+2, 1-3) = (-2, -2),

and

co-ordinates of Y' are (-2+2, 3-3) = (0, 0).

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Option (A) is correct.

8 0
3 years ago
Using the following figure, match the angles in the first column with their corresponding congruent angles in the second column.
Rus_ich [418]

Answer:

∠6 = ∠8

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Step-by-step explanation:

Lines 'p' and 'q' are the parallel lines and line 'l' is a transversal line intersecting these lines at two distinct points.

By the property of alternate interior angles,

∠3 = ∠5

By the property of vertically opposite angles,

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By the property of corresponding angles,

∠2 = ∠6

3 0
3 years ago
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