Question

Factor 1 - 2.25x 8.......

Answer 1

1-2.25x8=(1-1.5x^4)(1+1.5x^4)
=(1-√1.5 x²)(1+√1.5 x²)(1+1.5 x^4)
=(1-√√1.5   x)(1+√√1.5  x)(1+√1.5 x²)  (1+√1.5 x^4)

Answer 2

Answer with explanation:

We have to factorize the expression:

  $\rightarrow 1-2.25 x^8\\\\=(1)^2 - (1.5x^4)^2\\\\=(1-1.5 x^4)(1+1.5 x^4)\\\\=[1-(\sqrt{1.5}x^2)^2][1+(\sqrt{1.5}x^2)^2](1+1.5 x^4)\\\\=[1-x\times(1.5)^{\frac{1}{4}}][1+x\times(1.5)^{\frac{1}{4}}][1+(\sqrt{1.5}x^2)^2][1+1.5 x^4]$

Used the Identity to solve the problem

 $a^2-b^2=(a-b)(a+b)$