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iragen [17]
4 years ago
11

How did Democritus characterize atoms?

Chemistry
1 answer:
Afina-wow [57]4 years ago
4 0
He states that atoms are indivisible and indestructible
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On your first day working in a laboratory, you are told to make up 1 Liter of a 0.5 Molar Tris solution with a pH of 7.4. You me
GenaCL600 [577]

Answer:

60.57g of TRIS did you use

Explanation:

The concentration of the Tris solution buffer is 0.5 molar (That is, 0.5 moles per liter). As you need to make 1L, you need to have in the solution <em>0.5 moles of TRIS.</em>

<em />

To convert these moles of TRIS to grams you need to use the molecular weight of TRIS base (121.14g/mol), thus:

0.5 moles TRIS * (121.14g / mol) =

<h3>60.57g of TRIS did you use</h3>
7 0
3 years ago
Which of the following statements are true about whether atoms tend to gain<br> or lose electrons?
Dafna11 [192]

Answer:

C and D

Explanation:

Atoms with five, six or seven valance electrons gain electrons to complete the octet because it is more convenient for the atoms to gain three, two or one electron as compared to lose five, six or seven electrons. Thus atoms with five, six or seven valance electrons form negative ions by gaining electrons.

Atoms with one, two or three valance electrons lose the electrons to get complete octet because it is more convenient for the atoms to lose one two or three electrons as compared to gain the seven, six or five electrons. The atoms with one, two or three valance electrons form positive ions.

5 0
3 years ago
The cell potential of the following electrochemical cell depends on the gold concentration in the cathode half-cell: Pt(s)|H2(g,
Masja [62]

<u>Answer:</u> The concentration of Au^{3+} in the solution is 1.87\times 10^{-14}M

<u>Explanation:</u>

The given cell is:

Pt(s)|H_2(g.1atm)|H^+(aq.,1.0M)||Au^{3+}(aq,?M)|Au(s)

Half reactions for the given cell follows:

<u>Oxidation half reaction:</u> H_2(g)\rightarrow 2H^{+}(1.0M)+2e^-;E^o_{H^+/H_2}=0V ( × 3)

<u>Reduction half reaction:</u> Au^{3+}(?M)+3e^-\rightarrow Au(s);E^o_{Au^{3+}/Au}=1.50V ( × 2)

<u>Net reaction:</u> 3H_2(s)+2Au^{3+}(?M)\rightarrow 6H^{+}(1.0M)+2Au(s)

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=1.50-0=1.50V

To calculate the concentration of ion for given EMF of the cell, we use the Nernst equation, which is:

E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[H^{+}]^6}{[Au^{3+}]^2}

where,

E_{cell} = electrode potential of the cell = 1.23 V

E^o_{cell} = standard electrode potential of the cell = +1.50 V

n = number of electrons exchanged = 6

[Au^{3+}]=?M

[H^{+}]=1.0M

Putting values in above equation, we get:

1.23=1.50-\frac{0.059}{6}\times \log(\frac{(1.0)^6}{[Au^{3+}]^2})

[Au^{3+}]=1.87\times 10^{-14}M

Hence, the concentration of Au^{3+} in the solution is 1.87\times 10^{-14}M

7 0
3 years ago
Which of the following substances is classified as a solution?
Ainat [17]

Answer:

Salt water

Explanation:

Please mark me brainliest and thank me.

3 0
3 years ago
Read 2 more answers
What the equipment of diffusion?​
I am Lyosha [343]

Answer:

liquid

a semi permeable membrane

oxygen

Explanation:

plz give me brainiest

5 0
3 years ago
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