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3 years ago

Explain why ions become solvated in aqueous solution.

1 answer:

8 0

Ions <span>become solvated in aqueous solution for the main reason that the action has considered to have a partially negative charge while on the other hand, the anion has a partially positive charge. By definition, solvation is the chemical process wherein these anions and cations get surrounded by solvent ions.</span>

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The compound MgF is an example of a(n)

melamori03 [73]

It is metallic compound

7 0

3 years ago

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Which of the following reasons best explains why it is possible to separate a 1:1 mixture of 1-chlorobutane and 1-butanol by fra

KatRina [158]

Answer:

The boiling point of 1-chlorobutane is substantially lower than that of 1-butanol

Explanation:

Fractional distillation is a separation process based on difference in boiling point of two compounds.

1-chlorobutane is a polar aprotic molecule due to presence of polar C-Cl bond. Hence dipole-dipole intermolecular force exists in 1-chlorobutane as a major force.

1-butanol is a polar protic molecule. Hence dipole-dipole force along with hydrogen bonding exist in 1-butanol.

Therefore intermolecular force is stronger in 1-butanol as compared to 1-chlorobutane.

So, boiling point of 1-butanol is much higher than 1-chlorobutane.

Hence mixture of 1-chlorobutane and 1-butanol can be separated by fractional distillation based on difference in boiling point.

So, option (D) is correct.

6 0

3 years ago

Start with 100.00 mL of 0.10 M acetic acid, CH3COOH. The solution has a pH of 2.87 at 25 oC. a) Calculate the Ka of acetic acid

jasenka [17]

Answer: a) The $K_a$ of acetic acid at $25^0C$ is $1.82\times 10^{-5}$

b) The percent dissociation for the solution is $4.27\times 10^{-3}$

Explanation:

$CH_3COOH\rightarrow CH_3COO^-H^+$

cM 0 0

$c-c\alpha$ $c\alpha$ $c\alpha$

So dissociation constant will be:

$K_a=\frac{(c\alpha)^{2}}{c-c\alpha}$

Give c= 0.10 M and $\alpha$ = ?

Also $pH=-log[H^+]$

$2.87=-log[H^+]$

$[H^+]=1.35\times 10^{-3}M$

$[CH_3COO^-]=1.35\times 10^{-3}M$

$[CH_3COOH]=(0.10M-1.35\times 10^{-3}=0.09806M$

Putting in the values we get:

$K_a=\frac{(1.35\times 10^{-3})^2}{(0.09806)}$

$K_a=1.82\times 10^{-5}$

b) $\alpha=\sqrt\frac{K_a}{c}$

$\alpha=\sqrt\frac{1.82\times 10^{-5}}{0.10}$

$\alpha=4.27\times 10^{-5}$

$\% \alpha=4.27\times 10^{-5}\times 100=4.27\times 10^{-3}$

5 0

4 years ago

How many grams of water are produced when 35.8 grams of Calcium hydroxide reacts with lots of Hydrochloric acid?

Veseljchak [2.6K]

Are produced 72 grams of water in this reaction.

<h3>Mole calculation</h3>

To find the value of moles of a product from the number of moles of a reactant, it is necessary to observe the stoichiometric ratio between them:

$Ca(OH)_2 + 2HCl = > 2H_2O + CaCl_2$

Analyzing the reaction, it is possible to see that the stoichiometric ratio is 1:2, so we can perform the following expression:

$MM_{Ca(OH)_2} = 74.1g/mol$

$MM = \frac{g}{mol}$

$74.1 = \frac{35.8}{mol}\\mol = 2$

So, if there are 2 mols of Ca(OH)2:

Ca(OH)2 | H2O

$\frac{1mol}{2mol} =\frac{2mol}{xmol}$

$x = 4mol$

Finally, just find the number of grams of water using your molar mass:

$MM_{H_2O} = 18g/mol$

$18= \frac{m}{4}\\m = 72g$

So, 72 grams are produced of water in this reaction.

Learn more about mole calculation in: brainly.com/question/2845237

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2 years ago

Please help! USATestprep K12

NeX [460]

Answer:

its none above

Explanation:

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bar graphs have bars and numbers and diagrams have words and pictures so it D

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3 years ago

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