A regression line is a graphic representation of the regression equation expressing the hypothesized relationship between an outcome or dependent variable and one or more predictors or independent variables;

y= $2.01*1.93^{x}$

Correlation:

r=0.964

R-squared:

r²=0.9292

Hence, value of a and b is 2.17 and 1.95.

learn more about regression line here:

brainly.com/question/11340674

#SPJ1

8 0

2 years ago

Maddie bought 3 2/3 yards of satin ribbon at the craft store. She wanted to make hair bows for the cheer squad. Each bow require

kotegsom [21]

Answer:

Step-by-step explanation:

Given that:

Total yards of satin bought by Maddie = $3\frac{2}{3}$ yards

Number of yards required make one ribbon = $\frac{2}{3}$ yards

To find:

Number of complete bows that can be made ?

Solution:

First of all, let us learn about converting the mixed fraction to fractional form.

Formula:

$a\dfrac{b}{c} = \dfrac{a\times c+b}{c}$

Therefore, total yards of satin bought by Maddie can be written in fractional form as:

$3\dfrac{2}{3} = \dfrac{3\times 3+2}{3} = \dfrac{11}{3}$

One hair bow requires $\frac{2}{3}$ yards of ribbon.

Number of hair bows that can be made, can be found by dividing the total ribbon length by ribbon required for making one hair bow.

Answer is:

$\dfrac{\frac{11}{3}}{\frac{2}{3}}\\\Rightarrow \dfrac{11\times 3}{2\times 3}\\\approx 4$

4 hair bows can be made.

4 0

3 years ago

each time kim pour water from a jug into a glass, exactly 10% of the water remaining in the jug is used. What is the minimum num

Gnoma [55]

The <em><u>correct answer</u></em> is:

At least 7 times.

Explanation:

Since 10% of the water in the jug is removed each time, this means that 100-10=90% of the water remains.

After two times, we would have 0.9(0.9) = 0.81 = 81% of the water; each time she pours, the number of times 0.9 is multiplied by itself changes. This makes this an exponential inequality (it is not an equation, as we want "less than half of the water"):

$0.5 < 0.9^x$

To solve this, we will use logarithms:

$\log_{0.9}(0.5)$

4 0

3 years ago