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3 years ago

How far does a bus travel at 2.5 hours at 65mph

Mathematics

2 answers:

Lera25 [3.4K]3 years ago

7 0

It will drive 162.5 miles in 2.5 hours

oksian1 [2.3K]3 years ago

5 0

the bus goes 65 miles every hour. so: 1hr = 65mi

to find how many miles it goes every 2.5 hours, we multiply each side by 2.5:

2.5hrs = 162.5mi

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Solve: 7.2 + 3.5

oksano4ka [1.4K]

Hello~

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7 + 3.5

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3 years ago

Schools, peers, and co-workers are __________ because they influence or shape our self-concept, attitudes, and behaviors.

Bogdan [553]

Answer:

Agents of socialization

Step-by-step explanation:

A total institution is a closed social system where life is organized by norms, rules, schedules, whatever happens, within it it's determined by a single authority. These systems are designed to provide care to a population that is unable to care for themselves, and/or protect society from potential harm, examples of these institutions are mental health facilities, prisons or private boarding schools. Sociologically speaking these institution's purpose is resocialization and/or rehabilitation.
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I hope you find this information useful and interesting! Good luck!

3 0

3 years ago

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liq [111]

Answer:

2x2 - x + 3

Step-by-step explanation:

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4 years ago

What value of x makes x/20 and 3/4 proportionate

hodyreva [135]

The Answer is x=15. Good luck!

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3 years ago

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Here is a triangular pyramid and its net.

bazaltina [42]

Answer:

a) Area of the base of the pyramid = $15.6\ mm^{2}$

b) Area of one lateral face = $24\ mm^{2}$

c) Lateral Surface Area = $72\ mm^{2}$

d) Total Surface Area = $87.6\ mm^{2}$

Step-by-step explanation:

We are given the following dimensions of the triangular pyramid:

Side of triangular base = 6mm

Height of triangular base = 5.2mm

Base of lateral face (triangular) = 6mm

Height of lateral face (triangular) = 8mm

a) To find Area of base of pyramid:

We know that it is a triangular pyramid and the base is a equilateral triangle. $\text{Area of triangle = } \dfrac{1}{2} \times \text{Base} \times \text{Height} ..... (1)\\$