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enot [183]
3 years ago
12

Steven likes to skip rocks on the lake. If he skips 2 rocks 5 times, 4 rocks 3 times, and 6 rocks 2 times, how many skips does h

e do?
Mathematics
2 answers:
natulia [17]3 years ago
7 0
He skips 48 times and 10 times
mash [69]3 years ago
5 0
He does 34 skips.

10+12+12=34
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Determine the measure of an interior angle of the named regular polygon. If a side of the polygon is extended, determine the sup
ladessa [460]

Answer:

A) Each interior angle of the Regular Hexagon = 120°

B)The measure of the supplementary angle of an interior angle is  60°

Step-by-step explanation:

Regular Hexagon : A 6 sided polygon which has all 6 interior angles as  EQUAL is called a regular hexagon.

So, here are 6 interior angles of the hexagon are equal.

Also, Sum of all interior angles of an hexagon = 720°

Let us assume the each angle of the hexagon = m

⇒ m + m + m + m + m  + m = 720°

or, 6 m = 720°

or, m = 720° / 6 = 120°

⇒ Each interior angle of the Regular Hexagon = 120°

Now, a side is extended to form an exterior angle.

Let us assume the measure of that exterior angle  = k

⇒ k + m = 180 °   ( as k and m are SUPPLEMENTARY ANGLES)

or,  k = 180 - 120   = 60 °

or, k = 60 °

Hence,  the measure of the supplementary angle of an interior angle is  60°

6 0
3 years ago
What number is divisible by 2,3 and 6
UkoKoshka [18]
I believe it’s 12 but i could be wrong
8 0
3 years ago
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Convert the following unsigned binary number to unsigned decimal.<br><br> 110011.101
tangare [24]

Answer:

51.625

Step-by-step explanation:

Given a unsigned binary number, to calculate the unsigned decimal:

first, starting at dot, you list the positive powers of 2 from right to left beginning in 2^{0}  that is equal to “1”.  Increase by one the exponent in every power until you complete the total quantity of digits from the unsigned binary number. In this case, since dot to the left, the binary number has six digits (110011). That is to say that you get the followings powers: 2^{5}  2^{4}  2^{3} 2^{2}  2^{1}  2^{0}.

Second, do the same from dot to the right but this time, you list the negative powers of 2 from left to right beginning in 2^{-1} that is equal \frac{1}{2} = 0.5. so you get:    2^{-1}  2^{-2}  2^{-3}

Now, join two parts and you get:

2^{5}      2^{4}     2^{3}      2^{2}      2^{1}       2^{0}    2^{-1}      2^{-2}      2^{-3}

1        1       0       0       1       1.        1        0        1

Then, you write the equivalent of each of the power below from corresponding binary digit, like that:

2^{5}      2^{4}     2^{3}      2^{2}      2^{1}       2^{0}    2^{-1}      2^{-2}      2^{-3}

1        1       0       0       1       1.        1        0        1

|         |        |         |        |        |         |         |         |  

32    16      8       4       2       1       0.5   0.25   0.125  

Finally, you write under the line the equivalent of each power that corresponding to “1” and write “0” under the line, the one that corresponding to “0”, and you sum each one of finals values. Like that:

2^{5}      2^{4}     2^{3}      2^{2}      2^{1}       2^{0}    2^{-1}      2^{-2}      2^{-3}

1        1       0       0       1       1.        1        0        1

|         |        |         |        |        |         |         |         |  

32    16      8       4       2       1       0.5   0.25   0.125  

_______________________________________  

32    16      0       0       2       1       0.5     0      0.125  

32 + 16 + 0 + 0 + 2 + 1 + 0.5+ 0 + 0.125 = 51.625

So that the equivalent from unsigned binary number 110011.101 to unsigned decimal is 51.625

5 0
4 years ago
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astra-53 [7]

Essentially, the rule goes as so: odd + odd = even, even + even = even.

Although that may not be the answer you're looking for, it is a math rule that is never debunked and essentially the premises for why you get an even sum practically always depending on the numbers.

Hope this helps!

3 0
3 years ago
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Sam is filling up his pool. The water hose filled the 392 gallon pool in 49 minutes. At what rate did the hose fill the pool in
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Your answer would be 8 Hammond per minute. Hope this helps!
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