Question

An orchestra has twice as many woodwind instruments as brass instruments. There are a total of 150 brass and woodwind instruments. Write two different addition equations that describes this situation. Use w for woodwinds and b for brass

Answer 1

Answer:

$w+b=150$

Or

$2b+b=150$

Step-by-step explanation:

Given : An orchestra has twice as many woodwind instruments as brass instruments. There are a total of 150 brass and woodwind instruments.

To Find: Write two different addition equations that describes this situation.

Solution:

Let w be the woodwinds instruments..

Let b be the brass instruments.

We are given that An orchestra has twice as many woodwind instruments as brass instruments.

So, $w = 2b$

We are given that There are a total of 150 brass and woodwind instruments.

So, $w+b=150$

Or

$2b+b=150$

Hence two different addition equations that describes this situation are :

$w+b=150$

Or

$2b+b=150$

Answer 2

Answer: The two different addition equations that describes the given situation are,

w = 2 b

b + w = 150

Step-by-step explanation:

Here, w represents the number of woodwinds and b represents the number of brass instrument.

Since, There are twice as many woodwind instruments as brass instruments,

⇒ w = 2b

And, The total number of instruments = 150

⇒ w + b = 150

Hence, the equations that shows the given situation are,

w = 2 b,  b + w = 150