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iren [92.7K]
3 years ago
11

Rule for X-5,6,7,8 Y-20,24,28,32. What is rule for Y?

Mathematics
2 answers:
Lina20 [59]3 years ago
3 0
<h2>The rule for x is + 1, and the rule for y is + 4.</h2>
____ [38]3 years ago
3 0
Rule for Y is +1 because the numbers are increasing by 1
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Find the value of this expression if x = 4 and<br> y = -2.<br> ху/5
slavikrds [6]

Answer:

-1.6

Step-by-step explanation:

4x-2/5

=-8/5

=-1.6

8 0
2 years ago
Find the domain of the function f(x) = 7x2 + 8x - 15.
amm1812

Answer:

Domain is all real numbers or (negative infinity, positive infinity)

Step-by-step explanation:

Domain is all values of <em>x</em> (inputs) that will work with the function. Since a parabola has no limits for <em>x</em>, and all numbers work for <em>x</em>, then the domain can be any number. That leaves us with All Real Numbers as our answer.

5 0
3 years ago
Lena is converting 2/25 to a percent. What should she multiply the numerator and denominator of the fraction by to find the perc
NNADVOKAT [17]
A percent is a number out of 100, so you'd want to multiply the denominator to get 100. In this case, 25 would have to be multiplied by 4 to get 100. To keep the fractions equal to each other, you have to multiply the numerator by the same thing. 2*4=8. Therefore, your fraction would be 8/100 or 8%
7 0
3 years ago
Read 2 more answers
Please help! Please explain how to do this, I am so lost.
alexdok [17]
Ok, so we know that RST is equal to 6x+12
And RST is also equal to 78 + 3x-12
so we set them equal to each other

6x + 12 = 3x - 12 + 78
And simplify
3x = 54
x = 18

Finally, we solve for the angle with 18 for x

6(18) + 12
108 + 12
120

Hope this helps
8 0
3 years ago
What did sin theta/theta whisper worksheet answer key worksheet?
djyliett [7]
To evaluate
\lim_{\theta \to 0}  \frac{\sin\theta}{\theta}

First, we input 0, for theta in the function to obtain:
\frac{\sin0}{0} = \frac{0}{0}

This is an indeterminate form.

So, we apply L'Hopital's rule by differentiating the numerator and the denominator as follows:

\lim_{\theta \to 0} \frac{\sin\theta}{\theta}=\lim_{\theta \to 0} \frac{ \frac{d}{d\theta} (\sin\theta)}{\frac{d}{d\theta}\theta} \\  \\ =\lim_{\theta \to 0} \frac{\cos\theta}{1}=\cos0=1
7 0
2 years ago
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