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Bingel [31]
3 years ago
10

What did sin theta/theta whisper worksheet answer key worksheet?

Mathematics
1 answer:
djyliett [7]3 years ago
7 0
To evaluate
\lim_{\theta \to 0}  \frac{\sin\theta}{\theta}

First, we input 0, for theta in the function to obtain:
\frac{\sin0}{0} = \frac{0}{0}

This is an indeterminate form.

So, we apply L'Hopital's rule by differentiating the numerator and the denominator as follows:

\lim_{\theta \to 0} \frac{\sin\theta}{\theta}=\lim_{\theta \to 0} \frac{ \frac{d}{d\theta} (\sin\theta)}{\frac{d}{d\theta}\theta} \\  \\ =\lim_{\theta \to 0} \frac{\cos\theta}{1}=\cos0=1
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A number split evenly into 6 groups. in expression symbol.
deff fn [24]

Answered already okay. GFY.

7 0
3 years ago
Rewrite in simplest radical form 1 over x^(−3/6). Show each step of your process.
meriva

\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\\\ ~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}}

\bf \rule{34em}{0.25pt}\\\\ \cfrac{1}{x^{-\frac{3}{6}}}\implies x^{\frac{3}{6}}\implies x^{\frac{1}{2}}\implies \sqrt[2]{x^1}\implies \sqrt{x}

5 0
3 years ago
you can buy 5 cans of green beans at the village market for $3 you can buy 10 of the same cans of beans at Sams Club for $6.10 w
ioda

Each can of green beans costs  ($3.00/5) = 60¢  at the
village market, and  ($6.10/10) = 61¢  at Sam's Club.

If you're watching every penny, then that MIGHT be enough
of a difference to make you decide to buy your beans at the
village market, but not necessarily.

If, say, the village market is farther away from you, or if there are
other things you're going to get from Sam's anyway, then you
should buy your beans there too.

6 0
3 years ago
Mike took clothes to the cleaners three times last month.​ First, brought 4 shirts and of slacks and paid ​$11.45. Then brought
GenaCL600 [577]

Complete Question:

Mike took clothes to the cleaners three times last month.​ First, brought 4 shirts and 1 pair of slacks and paid ​$11.45. Then brought ​7 shirts, 2 pairs of​ slacks, and 2 sports and paid ​$35.39. ​Finally, brought 5 shirts and 2 sports and paid ​$21.43 . How much was charged for each​ shirt, each pair of​ slacks, and each sports​ coat?

Answer:

The charges

For each Shirt = $1.49

For each pair of slacks = $5.49

For each sports coat = $6.99

Step-by-step explanation:

Let Shirt = a

Let pair of slacks = b

Let sports coat = c

First, brought 4 shirts and 1 pair of slacks and paid ​$11.45

= 4a + b = 11.45 ..........Equation 1

b = 11.45 - 4a

Then brought ​7 shirts, 2 pairs of​ slacks, and 2 sports and paid ​$35.39

= 7a + 2b + 2c = 35.39.........Equation 2

5 shirts and 2 sports and paid ​$21.43

5a + 2c = 21.43............Equation 3

Hence:

4a + b = 11.45 ..........Equation 1

7a + 2b + 2c = 35.39.........Equation 2

Using elimination method

Multiply Equation 2 by the coefficient of b = 1 in Equation 1

Multiply Equation 1 by the coefficient of b = 2 in Equation 2

8a + 2b = 22.9 .......Equation 4

7a + 2b + 2c = 35.39.........Equation 2

Subtracting Equation 2 from Equation 4

= a - 2c = -12.49 ........Equation 5

a = -12.49 + 2c

Subtituting -12.49 + 2c for a in Equation 3

5a + 2c = 21.43............Equation 3

5(-12.49 + 2c) + 2c = 21.43

= -62.45 + 10c + 2c = 21.43

Collecting like terms

10c + 2c = 21.43 + 62.45

12c = 83.88

c = 83.88/12

c = 6.99

5a + 2c = 21.43............Equation 3

Substituting 6.99 for c in Equation 3

5a + 2(6.99) = 21.43

5a + 13.98 = 21.43

5a = 21.43 - 13.98

5a = 7.45

a = 7.45/5

a = 1.49

4a + b = 11.45 ..........Equation 1

Substituting 1.49 for a in Equation 1

4(1.49) + b = 11.45

b = 11.45 - 4(1.49)

b = 11.45 - 5.96

b = 5.49

Therefore, since the charges

For each shirt = a

The charges for each Shirt = $1.49

For each pair of slacks = b

The charges for each pair of slacks = $5.49

For each sports coat = c

The charges for each sports coat = $6.99

3 0
3 years ago
What is the degree of this polynomial?<br><br> 4m^8-9m^6+3m^9-6m^7
Klio2033 [76]

Answer:

this is a ninth degree polynomial in m

Step-by-step explanation:

Inspect the polynomial for the highest power of the variable m.  It is m^9.  Thus, this is a ninth degree polynomial in m.

7 0
2 years ago
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