<span>2/3 probability of drawing a green marble on the second draw.
If the marbles are replaced after each draw, the probability will always be 2/3 of a green marble being drawn. But for this problem, going to assume that the marbles are not replaced after each draw. So we have 2 possible scenarios.
1. The first marble drawn is green
This even happens with probability of 2/3 and leaves you with 7 green marbles and 4 blue marbles. So the probability of picking a green marble again is 7/11.
2. The first marble drawn is blue
This event happens with probability of 1/3 and leaves you with 8 green marbles and 3 blue marbles. So the probability of picking a green marble this time is 8/11
The total probability of picking a green marble on the 2nd pick is the sum of the product of each probability. So
2/3 * 7/11 + 1/3 * 8/11 = 14/33 + 8/33 = 22/33 = 2/3</span>
Try this solution:
1. In order to built the line required in the condition it need to determine its equation.
Using the coordinates of point B (5;2), if to substitute them into the given equation: 2=-3*5+b, ⇒ b=17. It means, that the equation of the line required in the condition is y= -3x+17.
2. The graph is in the attachment; point (0;17) is the intersection point of Y-axis and the line.
Answer:
(-3, 1) quadrant II (2)
Step-by-step explanation:
An image of the coordinate plane is show. The quadrants start at the top right and move around in the counter-clockwise direction. The x-axis is horizontal (side to side) and y-axis is vertical (up and down). Starting at the origin of the coordinate plane (0, 0) and going three blocks west (left) would put you at -3 on the x-axis. If you then proceed to go north (up) +1, you would now be at point (-3, 1) which is a (-x, +y) or in quadrant II.
Answer:
i don't see the question, but i can help you
Step-by-step explanation: