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Bingel [31]
3 years ago
10

What did sin theta/theta whisper worksheet answer key worksheet?

Mathematics
1 answer:
djyliett [7]3 years ago
7 0
To evaluate
\lim_{\theta \to 0}  \frac{\sin\theta}{\theta}

First, we input 0, for theta in the function to obtain:
\frac{\sin0}{0} = \frac{0}{0}

This is an indeterminate form.

So, we apply L'Hopital's rule by differentiating the numerator and the denominator as follows:

\lim_{\theta \to 0} \frac{\sin\theta}{\theta}=\lim_{\theta \to 0} \frac{ \frac{d}{d\theta} (\sin\theta)}{\frac{d}{d\theta}\theta} \\  \\ =\lim_{\theta \to 0} \frac{\cos\theta}{1}=\cos0=1
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3 years ago
You travel from point A to point B in a car moving at a constant speed of 70 km/h. Then you travel the same distance from point
tankabanditka [31]

Answer:

Yes, the average speed for the entire trip from A to C is equal to 80\frac{km}{h}

Step-by-step explanation:

The average speed of an object is defined as the distance traveled divided by the time elapsed. Velocity is a vector quantity, and average velocity can be defined as the displacement divided by the time. For the special case of straight line motion in the x direction, the average velocity takes the form:

V_a_v_e_r_a_g_e=\frac{x_2-x_1}{t_2-t_1}=\frac{Δx}{Δt}

If the beginning and ending velocities for the motion are known, and the acceleration is constant, the average velocity can also be expressed as:

V_a_v_e_r_a_g_e=\frac{V_1+V_2}{2}

We Know that:

V_1=70\frac{km}{h} \\\\V_2=90\frac{km}{h}

Replacing the values:

V_a_v_e_r_a_g_e=\frac{70+90}{2} =\frac{160}{2}=80\frac{km}{h}

5 0
3 years ago
What is the value of a1 of the geometric series? Sigma-Summation Underscript n = 1 Overscript infinity EndScripts 12 (negative o
worty [1.4K]

Answer:

12

Step-by-step explanation:

The given geometric series is

\sum_{n = 1}^{ \infty} 12( { -  \frac{1}{9} })^{n - 1}

We want to determine the first term of this geometric series.

Recall that the explicit formula is

a_{n} = 12( { -  \frac{1}{9} })^{n - 1}

To find the first term, we put n=1 to get:

a_{1} = 12( { -  \frac{1}{9} })^{1 - 1}

This gives us:

a_{1} = 12( { -  \frac{1}{9} })^{0}

a_{1} = 12(1) = 12

Therefore the first term is 12

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