Answer: "N" is considered as the size of the input that is being given in the algorithm.
Explanation: During a problem solving process , a algorithm is used to analyze the problem . Many function and steps are to be taken care of while analyzing algorithm. Among analyzing step, input is also given which is usually zero more than that . An input has a certain size which is given by the initial "N". The input size defines the length of the string for the input.
Answer: throw your computer out of the window because to hell with this question
Explanation:
Answer:
C. CMR systems
Explanation:
CMR or customer relationship management is a strategy that uses data analysis of customers to manage the interaction between a company and current and potential customers.
It analyses the data of client from different channels like wesites, email, social media,telephone log etc, describing and predicting potential decisions to be made to enhance customer service and acquisition.
Businesses that conduct telemarketing are required to access the Do-Not-Call Registry every 31 days in order to maintain an updated database of people.
<h3>What telemarketing firms do?</h3>
The act of telemarketing is known to be the act talking to potential or existing customers through the use of a telephone.
Conclusively, Note that Telemarketing can help a business firm to promote or boast their products or services, make their customer database stronger, bring about a lot of leads and appointments and others.
Learn more about telemarketing from
brainly.com/question/25974538
Answer:
boolean isEven = false;
if (x.length % 2 == 0)
isEven = true;
Comparable currentMax;
int currentMaxIndex;
for (int i = x.length - 1; i >= 1; i--)
{
currentMax = x[i];
currentMaxIndex = i;
for (int j = i - 1; j >= 0; j--)
{
if (((Comparable)currentMax).compareTo(x[j]) < 0)
{
currentMax = x[j];
currentMaxIndex = j;
}
}
x[currentMaxIndex] = x[i];
x[i] = currentMax;
}
Comparable a = null;
Comparable b = null;
if (isEven == true)
{
a = x[x.length/2];
b = x[(x.length/2) - 1];
if ((a).compareTo(b) > 0)
m = a;
else
m = b;
}
else
m = x[x.length/2];
