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Ronch [10]
3 years ago
8

a bottle contains 12 red marbles and 8 blue marbles. A marble is chosen at random and not replaced. Then a second marble is chos

en at random. Determine the probability that the two marbles are not the same color.

Mathematics
1 answer:
patriot [66]3 years ago
5 0
P(A)= \frac{12}{20} \cdot \frac{8}{19} + \frac{8}{20} \cdot \frac{12}{19}= \frac{12\cdot8}{20\cdot19} \cdot2=\frac{12\cdot4}{5\cdot19}= \frac{48}{95}

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A mixture of 30 pounds of candy sells for $1.10 a pound. The mixture consists of chocolates worth $1.50 a pound and chocolates w
astra-53 [7]
x-chocolate\ worth\ 1,50\$ \ per\ pound\\
y-chocolate\ worth\ 0,9\$\ per\ pound\\
\\\\
 \left \{ {{x+y=30} \atop {30*1,10=x*1,50+y*0,9}} \right.\\\\ \left \{ {{x=30-y} \atop {33=1,5x+0,9y}} \right. \\\\ Using \ substitution\ method:\\\\33=1,5(30-y)+0,9y\\\\
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3 0
3 years ago
How to write 1/4 as a decimal number.
Sveta_85 [38]

Answer:

0.25

Step-by-step explanation:

1 divided by 4

7 0
2 years ago
Read 2 more answers
Can someone please help?
Travka [436]

Answer:

The answer is in the explaination

Step-by-step explanation:

A + B = 180 degrees

14x - 72 = 180

14x = 108

x = 8

A = 5 times 8 plus 20

A = 60

3 0
3 years ago
Read 2 more answers
What does “ Classify each polynomial by degree and number of terms” mean?
MrMuchimi
Okay so I'm going to try and explain it to you as best as possible. So all they are basically telling you is to give it a name. A degree on a polynomial is the highest exponent on it and the number of terms is the number of numbers. For example: -5x^3 + 2x^2 - 7
This is a 3rd degree polynomial with 3 terms. All you have to do is look at the largest exponent and that is your degree and the number of numbers.
3 0
3 years ago
If you are reading this please help!!!!
Soloha48 [4]

Given:

1.  -3 x^{2}\left(4 x^{3}-7\right)\\$2. $(6 x-5)(2 x+3)$\\3. $(3 x-1)\left(x^{2}+5 x-2\right)$

To find:

The product of the polynomials.

Solution:

1. -3 x^{2}\left(4 x^{3}-7\right) =-3 x^{2}(4 x^{3}) -3 x^{2}(-7)

Multiply the numerical coefficient and add the powers of x.

                          =-12 x^{5}+21 x^{2}

2. (6 x-5)(2 x+3)=6 x(2 x+3)-5(2x+3)

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

                              =12 x^2+18x-10 x-15

                              =12 x^2+8x-15

3. (3 x-1)\left(x^{2}+5 x-2\right)=3 x(x^{2}+5 x-2)-1(x^{2}+5 x-2)

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

                                      =3x^{3}+15 x^2-6x-x^{2}-5 x+2

Add or subtract like terms together.

                                      =3x^{3}+14 x^2-11x+2

The answer for multiplying polynomials:

1. -12 x^{5}+21 x^{2}

2. \  12 x^2+8x-15

3. \ 3x^{3}+14 x^2-11x+2

3 0
3 years ago
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