Answer:
Hey mate, please describe your question perfectly.
8: slope is 1/2 and y intercept is 0
9: slope is 7/4 and y-intercept is 0
<span>0.00041649312 on a calc unless u wanna simplify :)
hope i helped best of luck :)
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This problem can be readily solved if we are familiar with the point-slope form of straight lines:
y-y0=m(x-x0) ...................................(1)
where
m=slope of line
(x0,y0) is a point through which the line passes.
We know that the line passes through A(3,-6), B(1,2)
All options have a slope of -4, so that should not be a problem. In fact, if we check the slope=(yb-ya)/(xb-xa), we do find that the slope m=-4.
So we can check which line passes through which point:
a. y+6=-4(x-3)
Rearrange to the form of equation (1) above,
y-(-6)=-4(x-3) means that line passes through A(3,-6) => ok
b. y-1=-4(x-2) means line passes through (2,1), which is neither A nor B
****** this equation is not the line passing through A & B *****
c. y=-4x+6 subtract 2 from both sides (to make the y-coordinate 2)
y-2 = -4x+4, rearrange
y-2 = -4(x-1)
which means that it passes through B(1,2), so ok
d. y-2=-4(x-1)
this is the same as the previous equation, so it passes through B(1,2),
this equation is ok.
Answer: the equation y-1=-4(x-2) does NOT pass through both A and B.
Answer:the area is = the length*the width
2x^2-11x+15= (2x-5)* the width
you have to divide 2x^2 - 11 x + 15 at 2x-5
2x^2-11x+15 | 2x-5
-2x*2+5x x-3
-------------
/ -6x+15
+6x-15
-----------------
/ /
the answer is X-3
Step-by-step explanation:
